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s344n2d4d5 [400]
3 years ago
11

Copyright Laws provide_______ for the owners of creative works.

Computers and Technology
1 answer:
viktelen [127]3 years ago
7 0
They provide protection
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Java-Script Concept quiz:
In-s [12.5K]

Answer:

Explanation:

1) the versions of JavaScript that are fully supported by all modern browsers ( Except internet explorer 9) are:

C. ECMAScript 3, ECMAScript 5

2) JavaScript is used to implement complex features on a_____

A. web page

3) computer programming tools that are used to store data are called____

C. variables

4) var name = Scott; is the code to create a ____ called "Scott"

D. None of the above

Scott is a variable

5) the key difference between "var" and "let" variables is that____

D. None of the above  

let is used to redefine a variable by using var to redefine may cause problems

6) Hoisting in JavaScript is the process whereby declarations get moved to the____

C. top

7) Im JavaScript, "/ /" is used to code____

A. comments

8) ______ data types have two potential values - true and false.

D. None of the above

Boolean is the data type and null is always false

9) Using ____ gives coders the ability to query data set data to create blueprints.

C. consoles

The Console object provides access to the browser's debugging console.

5 0
3 years ago
To save the changes to the layout of a table, click the Save button on the _____.
kari74 [83]
Quick access toolbar :)))))))))
7 0
3 years ago
(3.01 MC)
faust18 [17]

Answer:

The answer to this question is given below in the explanation section. However, the correct answer is C.

Explanation:        

In pyton tutrle graphic library is used to draw lines and graphics. So, Madison should use the turtile python library to show the rise and fall of stock prices in visual presentation (lines).

Other options are not correct because Python  use math module library for mathematical tasks, shape graphics library is used for drawing a graphic windows etc, while Video module library is used for video editing etc.

3 0
3 years ago
Pressing the Backspace key deletes the text to the of the insertion point. The left or the right?
hodyreva [135]

The answer is:

Left

The backspace key only deletes whatever way the point is pointing to. In this case, it is to the left.

Correct me if i'm wrong.  

4 0
3 years ago
Read 2 more answers
Given an array A of size N, and a number K. Task is to find out if it is possible to partition the array A into K contiguous sub
Dennis_Churaev [7]

Answer: First lets solve the Prerequisite part

Lets say we have an input array of N numbers {3,2,5,0,5}. We have to  find number of ways to divide this array into 3 contiguous parts having equal sum. So the output for the above input array will be 2 as there are 2 ways to divide the array. One is (3,2),(5),(0,5) and the other is (3,2),(5,0),(5).

Following are the steps to achieve the above outcome.

  • Let p and q point to the index of array such that sum of array elements from 0 to p-1 is equal to sum of array elements from p to q which is equal to the sum of array elements from q+1 to N-1.  
  • If we see the array we can tell that the sum of 3 contiguous parts is 5. So the condition would be that sum of all array elements should be equal to 5 or sum of each contiguous part is equal to sum of all array elements divided by 5.
  • Now create 2 arrays prefix and postfix of size of input array. Index p of prefix array carries sum of input array elements from index 0 to index p. Index q of postfix array carries sum of input array elements from index p to index N-1
  • Next move through prefix array suppose at the index p of prefix array : value of prefix array == (sum of all input array elements)/5.
  • Search the postfix array for p index found above. Search it starting from p+2 index. Increment the count variable by 1 when the value of postfix array =(sum of all input array elements)/5 and push that index of postfix array into a new array. Use searching algorithm on new array to calculate number of values in postfix array.

Now lets solve the main task

We have an array A of size N and a number K. where A[]= {1,6,3,4,7} N=5 and K=3. We have to find if its possible to partition A into 3 contiguous subarrays such that sum of elements in each subarray is the same. It is possible in this example. Here we have 3 partitions (1,6),(3,4),(7) and sum of each of subarrays is same (1+6) (3+4) (7) which is 7.

Following are the steps to achieve the above outcome.

  • In order create K contiguous subarrays where each subarray has equal sum, first check the condition that sum of all elements in the given array should be divisible by K. Lets name another array as arrsum that will be the size of array A. Traverse A from first to  last index and keep adding current element of A with previous value in arrsum. Example A contains (1,6,3,4,7} and arrsum has {1,7,10,14,21}
  • If the above condition holds, now check the condition that each subarray or partition has equal sum. Suppose we represent sum1 to sum of all element in given array and sum2 of sum of each partition then: sum2 = sum2 / K.
  • Compare arrsum to subarray, begining from index 0 and when it becomes equal to sum2 this means that end of one subarray is reached. Lets say index q is pointing to that subarray.
  • Now from q+1 index find p index in which following condition holds: (arrsum[p] - arrsum[q])=sum2
  • Continue the above step untill K contigous subarrays are found. This loop will break if, at some index, sum2 of any subarray gets greater than required sum2 (as we know that every contiguous subarray should contain equal sum).

A easier function Partition for this task:

int Partition(int A[], int N, int k) // A arra y of size N and number k

{      int sum = 0;    int count = 0;  //variables initialization    

   for(int j = 0; j < N; j++)  //Loop that calculates sum of A

  sum = sum + A[j];        

  if(sum % k != 0) //checks condition that sum of all elements of A should be //divisible by k

   return 0;        

   sum = sum / k;  

   int sum2 = 0;  //represents sum of subarray

  for(int j = 0; j < N; j++) // Loop on subarrays

  {      sum2=sum2 + A[j];  

   if(sum2 == sum)    { //these lines locates subarrays and sum of elements //of subarrays should be equal

       sum2 = 0;  

       count++;  }  }  

/*calculate count of subarrays whose

sum is equal to (sum of complete array/ k.)

if count == k print Yes else print No*/

if(count == k)    

return 1;  

   else

   return 0;  }

6 0
3 years ago
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