Answer:
a. 0.01
b. 0.001
c. The identification field of the packet fragment can be used to uniquely identify and collate the fragments lost in transmission.
Explanation:
The probability of losing a packet is 10% or 0.1, so the probability of losing the packet twice during transmission;
= 0.1 x 0.1 = 0.01
When any fragments have been part of the transmission, the probability of the packet is dependent on the fragments;
= 0.01 x 0.1 = 0.001
The identification field is a unique 16-bit value assigned to an IPv4 packet, when a packet is fragmented for transmission, its field is used to collate the unique fragments in the packet.
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Answer:
Console.WriteLine("Format Double: {0:n3}", num); //formatting output with 3 digit decimal point
Explanation:
Following are the program in c#
using System; // namespace
using System.Collections.Generic;
using System.Linq;
using System.Text;
namespace Tasks
{
class Program
2 // program2
{
static void Main(string[] args) // Main function
{
double num = 958254.73789621; // variables
Console.WriteLine("Format Double: {0:n3}", num); //formatting output with 3 digit decimal point
Console.Read();
}
}
}
Output:
Format Double : 958254.737
Here we have declared a variable num of type double which store the value num=958254.73789621. To do format with the double number i used a syntax {0:n3}. This syntax {0:n3}is separated with :(colon) here 0 represent the value before the decimal point that is 958254 and n3 represent the value upto 3 decimal points. Hence this statement give the output with three digit after the decimal point .
The least common multiple (LCM) of 78, 90, and 140 is: 16,380
78 × 210 = 16,380
90 × 182 = 16,380
140 × 117 = 16,380
