Answer:
a. 100.
b. 31500.
Explanation:
So, we are given the following data which is going to help in solving this particular question.
The time required to execute (on the average) = 1/2 microsecond , a page fault takes of processor time to handle = 250 microseconds and the disk time to read in the page = 10 milliseconds.
Thus, the time taken by the processor to handle the page fault = 250 microseconds / 1000 = 0.25 milliseconds.
The execution time = [ 1/2 microseconds ]/ 1000 = 0.0005 milliseconds.
The number of Pages sent in a second by the disc = 1000/10 milliseconds = 100.
Assuming U = 1.
Hence, the disc transfer time = [2/3 × 1 } + [ 1/3 × 0.25 milliseconds + 15 ] × 2.
=0.667 + 15.083.
= 15.75 millisecond.
Average number of instruction = 15.75/0.0005 = 31500.
all pictures, images, clip art, shapes are in the insert tab
Answer:
see explaination
Explanation:
I made use of python program to solve this.
text file name with fun.txt.
6 fun. 3 hello 10 <> 2 25 4 wow!
Program code:
import re
file = open('fun.txt','r') #for reading file
strings="" #declaring empty string
for k in file:
strings=strings+k #all character in file is storing in strings variable for do operations
pattern = '\s' #for pattern \s is for space
result = re.split(pattern, strings) #split the string with space
for k in range(len(result)): #loop through the list of string
if(k%2) == 0: #checking for integer to time of string
p=int(result[k])
print(result[k+1] *p) #print times of the string(k+1)
Check attachment for output
the ip nat inside source command to link the inside local and inside global addresses
I hope this helps! :)
Answer:
true
Explanation:
everything is computerized. banks, shopping, financial business records, ect
