Answer:
(foh)(6) = -29
Step-by-step explanation:
(f o h)(6) is f(h(x)) when x = 6.
We have that:
f(x) = 4x - 1
h(x) = -x-1
f(h(x)) = 4(-x-1) - 1 = -4x - 4 - 1 = -4x - 5
(foh)(6) = -4(6) - 5 = -29
(foh)(6) = -29
Answer:
8.80 if it's the 40°/.
2.20 if it's the 10°/. processing fee
13.20 for how much he paid
Answer:
1) C) sin(θ) = 119/169
2) D) cos(θ) = 120/169
Step-by-step explanation:
The mnemonic SOH CAH TOA expresses the relationships you need for answering these questions.
Sin(θ) = Opposite/Hypotenuse = 119/169 . . . . . problem 1
Cos(θ) = Adjacent/Hypotenuse = 120/169 . . . . problem 2
Answer:
1/2 pound.
Step-by-step explanation:
Conversions: 48 oz = 3 lb
The ratio in the new pot is 3*2 tbs : 3 pounds , or just 6:3, which simplifies to 2:1. This means for every two tbs of powder, 1 lb of beef is used. This means that for every one tbs, 1/2 lb of beef is used.
Answer:
Lower limit: 113.28
Upper limit: 126.72
Step-by-step explanation:
Problems of normally distributed samples are solved using the z-score formula.
In a set with mean
and standard deviation
, the zscore of a measure X is given by:

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:

Middle 60%
So it goes from X when Z has a pvalue of 0.5 - 0.6/2 = 0.2 to X when Z has a pvalue of 0.5 + 0.6/2 = 0.8
Lower limit
X when Z has a pvalue of 0.20. So X when 




Upper limit
X when Z has a pvalue of 0.80. So X when 



