There is 6 1/8ths in 3/4ths
Answer:
<h2>2</h2>
Step-by-step explanation:
Given g(x)=5x-4 and g(x)=f^{-1}(x)-3
Substituting g(x) = 5x-4 into the second equation we have;
5x-4 = f^{-1}(x)-3
f^{-1}(x) = 5x-4+3
f^{-1}(x) = 5x-1
To get f(x), let us first make y to be equal f^{-1}(x)
y = 5x-1
expressing x in terms of y to get f(x), we have;
5x = y+1
x = y/5+1/5
replacing y with x, we will have;
y = x/5 + 1/5
F(x) = x/5 + 1/5
Comparing x/5 + 1/5 with ax+b, a = 1/5 and b = 1/5
5a + 5b = 5(1/5)+ 5(1/5)
5a+5b = 1+1
5a+5b = 2
Answer:
4/7
Step-by-step explanation:
hope this helps
Answer:


Step-by-step explanation:
Let
. We have that
if and only if we can find scalars
such that
. This can be translated to the following equations:
1. 
2.
3. 
Which is a system of 3 equations a 2 variables. We can take two of this equations, find the solutions for
and check if the third equationd is fulfilled.
Case (2,6,6)
Using equations 1 and 2 we get


whose unique solutions are
, but note that for this values, the third equation doesn't hold (3+2 = 5
6). So this vector is not in the generated space of u and v.
Case (-9,-2,5)
Using equations 1 and 2 we get


whose unique solutions are
. Note that in this case, the third equation holds, since 3(3)+2(-2)=5. So this vector is in the generated space of u and v.