Answer:
1 - Variable
2 - Corfficient
3 - Term
4 - Constant
Step-by-step explanation:
So, I am pretty srue the way the boxes are now is the correct way already. (I should be wrong?)
Answer:
The question ?
Step-by-step explanation:
Answer:
Any figure?
Step-by-step explanation:
Answer:
(a) 218.6 N
(b) 97.14 N
Step-by-step explanation:
When the system is in equilibrium, the net torque on the system is zero.
AC = 1.5 m, CD = 2.3 m, DB = 5 - 1.5 - 2.3 = 1.2 m
Let the centre of gravity of plank is at G.
AG = 2.5 m, CG = 2.5 - 1.5 = 1 m, GB = 2.5 m
(a) Let the reaction at C is R and at D is R'.
R + R' = 29 x 9.8 = 284.2 N ... (1)
Take the torque about C.
29 x 9.8 x CG = R' x GD
29 x 9.8 x 1 = R' x 1.3
R' = 218.6 N
(b) Take the torque about D.
6 x 9.8 x AD = R x CD
6 x 9.8 x (1.5 + 2.3) = R x 2.3
R = 97.14 N
Answer:
They weigh 1/6
Step-by-step explanation:
So what you do is Divide 1/4 bye 1 1/2 so that you can figure out how much 1 1/2 bags weigh and that equals 1/6
