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ValentinkaMS [17]
3 years ago
9

Identify the logarithmic form of 4^−2 = 0.0625.

Mathematics
1 answer:
Vikki [24]3 years ago
3 0

Answer:

  \log_4{(0.0625)}=-2

Step-by-step explanation:

The logarithmic form of ...

  \displaystyle b^e=v

is ...

  \log_b{(v)}=e

The exponent is the logarithm of the value. The base of the logarithm is the base of the exponential term.

Filling in your numbers, b=4, e=-2, v=0.0625, you have ...

  \log_4{(0.0625)}=-2

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