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Mademuasel [1]
3 years ago
15

Please Help!! George tells you that when variables are in the denominator, the equation becomes unsolvable. "There is a value fo

r x that makes the denominator zero, and you can't divide by zero," George explains. Using complete sentences, demonstrate to George how the equation is still solvable
Mathematics
2 answers:
hammer [34]3 years ago
8 0
Hello there.
<span>
Please Help!! George tells you that when variables are in the denominator, the equation becomes unsolvable. "There is a value for x that makes the denominator zero, and you can't divide by zero," George explains. Using complete sentences, demonstrate to George how the equation is still solvable
</span>
x = -10
luda_lava [24]3 years ago
5 0
For the answer to the question above, I'll provide a solution to my answer below.
(4 / 5) + (3 / x) = (1/2) 

<span>x cannot equal 0 </span>

<span>(4x + 15) / 5x = 1/2 </span>
<span>2(4x + 15) = 5x </span>
<span>8x + 30 = 5x </span>
<span>3x = -30 </span>
<span>x = -10
</span>I hope my answer helped you. Feel free to ask more questions. Have a nice day!
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hichkok12 [17]

Meant to put the letter A

5 0
3 years ago
HELP
Otrada [13]

Answer:

(x + 2)² + (y + 9)² = 49

Step-by-step explanation:

Equation:

(x - h)² + (y - k)² = r²

(x - -2)² + (y - -9)² = 7²

(x + 2)² + (y + 9)² = 49

5 0
3 years ago
Read 2 more answers
Given the functionf ( x ) = x^2 + 7 x + 10/ x^2 + 9 x + 20
vladimir1956 [14]

<em>x = -4 is a vertical asymptote for the function.</em>

<h2>Explanation:</h2>

The graph of y=f(x) is a vertical has an asymptote at x=a if at least one of the following statements is true:

1) \ \underset{x\rightarrow a^{-}}{lim}f(x)=\infty\\ \\ 2) \ \underset{x\rightarrow a^{-}}{lim}f(x)=-\infty \\ \\ 3) \ \underset{x\rightarrow a^{+}}{lim}f(x)=\infty \\ \\ 4) \ \underset{x\rightarrow a^{+}}{lim}f(x)=\infty

The function is:

f(x)=\frac{x^2+7x+10}{x^2+9x+20}

First of all, let't factor out:

f(x)=\frac{x^2+5x+2x+10}{x^2+5x+4x+20} \\ \\ f(x)=\frac{x(x+5)+2(x+5)}{x(x+5)+4(x+5)} \\ \\ f(x)=\frac{(x+5)(x+2)}{(x+5)(x+4)} \\ \\ f(x)=\frac{(x+2)}{(x+4)}, \ x\neq  5

From here:

\bullet \ When \ x \ approaches \ -4 \ on \ the \ right: \\ \\ \underset{x\rightarrow -4^{+}}{lim}\frac{(x+2)}{(x+4)}=? \\ \\ \underset{x\rightarrow -4^{+}}{lim}\frac{(-4^{+}+2)}{(-4^{+}+4)} \\ \\ \\ The \ numerator \ is \ negative \ and \ the \ denominator \\ is \ a \ small \ positive \ number. \ So: \\ \\ \underset{x\rightarrow -4^{+}}{lim}\frac{(x+2)}{(x+4)}=-\infty

\bullet \ When \ x \ approaches \ -4 \ on \ the \ left: \\ \\ \underset{x\rightarrow -4^{-}}{lim}\frac{(x+2)}{(x+4)}=? \\ \\ \underset{x\rightarrow -4^{-}}{lim}\frac{(-4^{-}+2)}{(-4^{-}+4)} \\ \\ \\ The \ numerator \ is \ a \ negative \ and \ the \ denominator \\ is \ a \ small \ negative \ number \ too. \ So: \\ \\ \underset{x\rightarrow -4^{-}}{lim}\frac{(x+2)}{(x+4)}=+\infty

Accordingly:

x=-4 \ is \ a \ vertical \ asymptote \ for \\ \\ f(x)=\frac{x^2+5x+2x+10}{x^2+5x+4x+20}

<h2>Learn more:</h2>

Vertical and horizontal asymptotes: brainly.com/question/10254973

#LearnWithBrainly

5 0
3 years ago
In the standard (x, y) coordinate plane, what is the slope of the line joining the points (3,7) and (4,−8)?
rjkz [21]
We know that the slope formula is m = (y1 - y2)/(x1 - x2)
Your points are: (3, 7) and (4, -8)
In this case,
x1 = 3
x2 = 4
y1 = 7
y2 = -8
Now, just plug in the numbers:
m = (7 - -8)/(3-4)
m = 15/-1
m = -15
Your slope is -15.
7 0
3 years ago
Stanley has $18 to spend on packs of trading cards that cost 1.50 each. The inequality 18x 1.5p represents the number of packs p
aev [14]

Answer:12 packs

Step-by-step explanation:4.5x4 is 18 then u divided 4.5,3 times to make 1.5 after that 3x4=12 or you could divide 18 by 1.5 and get the same answer

8 0
3 years ago
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