Answer:
UV=29
Step-by-step explanation:
In right triangles AQB and AVB,
∠AQB = ∠AVB ...(i) {Right angles}
∠QBA = ∠VBA ...(ii) {Given that they are equal}
We know that sum of all three angles in a triangle is equal to 180 degree. So wee can write sum equation for each triangle
∠AQB+∠QBA+∠BAQ=180 ...(iii)
∠AVB+∠VBA+∠BAV=180 ...(iv)
using (iii) and (iv)
∠AQB+∠QBA+∠BAQ=∠AVB+∠VBA+∠BAV
∠AVB+∠VBA+∠BAQ=∠AVB+∠VBA+∠BAV (using (i) and (ii))
∠BAQ=∠BAV...(v)
Now consider triangles AQB and AVB;
∠BAQ=∠BAV {from (v)}
∠QBA = ∠VBA {from (ii)}
AB=AB {common side}
So using ASA, triangles AQB and AVB are congruent.
We know that corresponding sides of congruent triangles are equal.
Hence
AQ=AV
5x+9=7x+1
9-1=7x-5x
8=2x
divide both sides by 2
4=x
Now plug value of x=4 into UV=7x+1
UV=7*4+1=28+1=29
<u>Hence UV=29 is final answer.</u>
Answer:
16-5x
Step-by-step explanation:
ArrayAn arrangement of objects in equal rowscolumna vertical group of items often found in an arraycommutative property<span>two factors can be multiplied in either order to find the product
ex.) 3 x 4 = 12
ex.) 4 x 3 = 12</span>distributive property<span>To multiply a sum by a number, multiply each addend by the number outside the parentheses.
ex. ) 12 x 3 = (10 x 3) + (2 x 3)</span>divisionAn operation in which we make parts out of a number, which are equalequationA mathematical sentence that contains an equals sign.factorone of two or more numbers, that when multiplied together produce a given productmethoda way of doing somethingmultiplicationAn operation used for the shortening of repeated additionnumber bonda model showing part, part, whole relationshipsnumber of groupsfactor in a multiplication problem that refers to the total equal groupsnumber sentenceA complete sentence that uses numbers and symbols instead of wordspictureillustrate, show, represent, portray, or depictquotientthe answer when one number is divided by another ex.) 14 / 2 = 7repeated additionadding equal groups together ex.) 2 + 2 + 2 + 2rowa horizontal group of items often found in an arraysize of groupsfactor in a multiplication problem that refers to the how many in each grouptape diagramA drawing that looks like a segment of tape, used to illustrate number relationships.unitone segment of a partitioned tape diagramProductThe answer to a multiplication problemRepresents<span>What the number you found stands for in your problem.</span>
I honestly don't know if this is correct but it might be i think its the middle one y=f(x)=x to the second power
It would be 16 more 6th graders that are not in either band or orchestra.
15 6th Graders in band
9 6th Graders in both classes
+18 6th Graders in orchestra
-----
42 6th Graders in either class
100 6th Graders in total
-42 6th Graders in either class
-------
58 6th Graders in neither class
58-42= 16 more 6th Graders that are not in either class
You're welcome :)
