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MariettaO [177]
3 years ago
5

Simplify the following. 1. a4 – 2a – 3a4 – 3a + 1

Mathematics
2 answers:
fredd [130]3 years ago
8 0

Answer:

-2a^4 - 5a +1

Step-by-step explanation:

I dunno if this is right but i got this.

boyakko [2]3 years ago
5 0

Answer:

− 2 a 4 − 5 a + 1

Step-by-step explanation:

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Simplify (2+7) divided by (7-2 times 2)
Step2247 [10]
1.111.... so just right 1.2
3 0
3 years ago
Classify the scenarios based on whether they are observational studies, experimentsor surveys. Scenarlo A: Twenty employees of a
Alex777 [14]

Answer:

Scenario A: Survey

Scenario B: Observational Studies

Scenario C: Experiment

Scenario D: Survey

If it not the answer you can correct me

6 0
3 years ago
The population of Henderson City was 3,381,000 in 1994, and is growing at an annual rate 1.8%
liq [111]
<h2>In the year 2000, population will be 3,762,979 approximately. Population will double by the year 2033.</h2>

Step-by-step explanation:

   Given that the population grows every year at the same rate( 1.8% ), we can model the population similar to a compound Interest problem.

   From 1994, every subsequent year the new population is obtained by multiplying the previous years' population by \frac{100+1.8}{100} = \frac{101.8}{100}.

   So, the population in the year t can be given by P(t)=3,381,000\textrm{x}(\frac{101.8}{100})^{(t-1994)}

   Population in the year 2000 = 3,381,000\textrm{x}(\frac{101.8}{100})^{6}=3,762,979.38

Population in year 2000 = 3,762,979

   Let us assume population doubles by year y.

2\textrm{x}(3,381,000)=(3,381,000)\textrm{x}(\frac{101.8}{100})^{(y-1994)}

log_{10}2=(y-1994)log_{10}(\frac{101.8}{100})

y-1994=\frac{log_{10}2}{log_{10}1.018}=38.8537

y≈2033

∴ By 2033, the population doubles.

4 0
3 years ago
The Acme Company manufactures widgets. The distribution of widget weights is bell-shaped. The widget weights have a mean of 37 o
just olya [345]

Answer:

a) 68 % will lie between 30 and 44 ounces

b) between 23 and 44 ounces will lie 81,5 %

Step-by-step explanation: See Annex

a) Normal Distribution  N ( 37, 7)

The Empirical Rule establishes that 68 % of values will be at

μ  ±  1 σ      where μ is the mean and σ the standard deviation

Then:   37 - 7  = 30    and 37 + 7 = 44

68 % of the values will lie between  30 and 44 ounces

b) And between  23 and 44 we should find:

We have 95 %  of values between

μ  ± 2*σ  

In our case to the left of the value (mean 0 ) and up to the value 23 we get 95/2 = 47,5 % and to the right of the value (mean 0 ) and up to 44 we half 68/2 = 34 %

Then between 23 and 44, we have 47,5 + 34 = 81,5 %

8 0
3 years ago
The problem for my last question. Plz answer!
Svetlanka [38]

Answer:

Find the difference between 4.5 and 40 which is 35.5 then divided that by 100 since you want the percent and that equals 0.35 which is 35%

4 0
3 years ago
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