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FromTheMoon [43]
3 years ago
5

The perimeter of a rectangle must be greater than 70 cm, but the length cannot be greater than 30 cm and the width cannot be gre

ater than 20 cm. What is a possible combination for the length and width of the rectangle?
Answers:

W=15 & L=25


W=10 & L=40


W=10 & L=20


W=30 & L=40
Mathematics
1 answer:
Jlenok [28]3 years ago
3 0
<span>W=15 & L=25

character requirement

</span>
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Which operation would help solve for w?
Vilka [71]

Answer:

B. Divide each side by 8

Step-by-step explanation:

Here is how:

8w ÷ 8 = 72 ÷ 8

w = 72 ÷ 8

w = 9

6 0
3 years ago
Helppppppppppp meeeee​
tatuchka [14]

Answer:

y = -2x + 3

Step-by-step explanation:

Let's just put the three points together.

(-1, 5) (-4, 11) (-7, 17)

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Plug in using (-1, 5) and (-4, 11)

11 - 5/-4 + 1 = 6/-3 (simplify)

-2 is the slope

Now plug in (-7, 17) in the equation to get b or the y-intercept)

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8 0
3 years ago
Determine ſ(2) where f(x) =x+1/4x-2
umka2103 [35]
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6 0
2 years ago
A florist needs several pieces of ribbon that are 5 and 1/2 inches long if she begins with a piece of ribbon that is 264 inches
dimaraw [331]

Answer:

  48

Step-by-step explanation:

(264 in)/(5.5 in/piece) = (264/5.5) pieces = 48 pieces

_____

Division is the usual shortcut for repeated subtraction. You could subtract 5.5 from 264 until you get to zero. You would have to do 48 subtractions. It is easier to divide 264 by 5.5 to see how many times it goes.

8 0
3 years ago
I'm confused. Can someone help?
VARVARA [1.3K]

a.

The polynomial w^2+18w+84 cannot be factored

The perfect square trinomial is w^2+18w + 81

----------

The reason the original can't be factored is that solving w^2+18w+84=0 leads to no real solutions. Use the quadratic formula to see this. The graph of y = x^2+18x+84 shows there are no x intercepts. A solution and an x intercept are basically the same. The x intercept visually represents the solution.

w^2+18w+81 factors to (w+9)^2 which is the same as (w+9)(w+9). We can note that w^2+18w+81 is in the form a^2+2ab+b^2 with a = w and b = 9

================================================

b.

The polynomial y^2-10y+23 cannot be factored

The perfect square trinomial is y^2-10y + 25

---------

Using the quadratic formula, y^2-10y+23 = 0 has no rational solutions. The two irrational solutions mean that we can't factor over the rationals. Put another way, there are no two whole numbers such that they multiply to 23 and add to -10 at the same time.

If we want to complete the square for y^2-10y, we take half of the -10 to get -5, then square this to get 25. Therefore, y^2-10y+25 is a perfect square and it factors to (y-5)^2 or (y-5)(y-5)

8 0
3 years ago
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