Ask question

Ask question

All categories

2 years ago

7

On a coordinate plane, point A is located at (7, 4), and point B is located at (-8, 4). What is the distance between the two poi

nts? *
-1
3
15
56

1 answer:

wel2 years ago

4 0

Answer:

Solution given;

A(x1,y1)=(7,4)

B(x2,y2)=(-8,4)

distance AB=?

we have

d= $\sqrt{(x2-x1) ²+(y2-y1) ²}$

AB= $\sqrt{(-8-7)²+(4-4)²}$

AB=15 units

the distance between the two points is 15 units.

You might be interested in

The perimeter of Dawna's new flat screen television is 112 inches. The ratio of its length to width is 4:3. Wire and solve an al

Dmitry_Shevchenko [17]

Hey there,
Length = 4x
Width = 3x
Perimeter = 112 inches
4x + 3x + 4x + 3x = 112 inches
14x = 112 inches
x = 112 inches / 14
= 8 inches
Length = 8 inches x 4
= 32 inches
Width = 8 inches x 3
= 24 inches

Hope this helps :))

<em>~Top♥</em>

5 0

2 years ago

Read 2 more answers

Pls explain to me how to find the value of x.

sladkih [1.3K]

Here are the pictures of the steps I took when solving it as well as the answer to what X is

4 0

3 years ago

Help asap please :(<br><br> Find the surface area of the composite figure.

Liono4ka [1.6K]

Answer:

136 in²

Step-by-step explanation:

8x2=16

6x2=12

6x2=12

6x2=12

10x2=20

10x2=20

10x2=20

8x2=16

2x2=4

2x2=4

136 in²

8 0

2 years ago

Please help ASAP don’t mind the scribbles

hjlf

U = 1

L = 0

R = -2

I = 24

M = 17

H = -3

E = 100

S = -439

O = 11

B = -6

T = -41

D = 19

C = 206

<em>Hope this helped ! :)</em>

8 0

3 years ago

In a certain Algebra 2 class of 30 students, 19 of them play basketball and 12 of them play baseball. There are 8 students who p

Alenkinab [10]

Answer:

Probability that a student chosen randomly from the class plays basketball or baseball is $\frac{23}{30}$ or 0.76

Step-by-step explanation:

Given:

Total number of students in the class = 30

Number of students who plays basket ball = 19

Number of students who plays base ball = 12

Number of students who plays base both the games = 8

To find:

Probability that a student chosen randomly from the class plays basketball or baseball=?

Solution:

$P(A \cup B)=P(A)+P(B)-P(A \cap B)$ ---------------(1)

where

P(A) = Probability of choosing a student playing basket ball

P(B) = Probability of choosing a student playing base ball

P(A \cap B) = Probability of choosing a student playing both the games

<u>Finding P(A)</u>

P(A) = $\frac{\text { Number of students playing basket ball }}{\text{Total number of students}}$

P(A) = $\frac{19}{30}$ --------------------------(2)

<u>Finding P(B)</u>

P(B) = $\frac{\text { Number of students playing baseball }}{\text{Total number of students}}$

P(B) = $\frac{12}{30}$ ---------------------------(3)

<u>Finding $P(A \cap B)$ </u>

P(A) = $\frac{\text { Number of students playing both games }}{\text{Total number of students}}$

P(A) = $\frac{8}{30}$ -----------------------------(4)

Now substituting (2), (3) , (4) in (1), we get

$P(A \cup B)= \frac{19}{30} + \frac{12}{30} -\frac{8}{30}$

$P(A \cup B)= \frac{31}{30} -\frac{8}{30}$

$P(A \cup B)= \frac{23}{30}$

7 0

2 years ago