1 rabbit
6 elephants
12 monkeys
12 parrots
31 animals all together
(can I get brainliest answer?)
Answer:
-0,046875
Step-by-step explanation:

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Sorry I don't know anything about that!
Hope this helps somehow, Ayitzdaisy!
Assuming no cubes are hidden from view, the base view (as if you're looking from underneath the figure) would have a 2 x 2 square of cubes, plus one at the top. This means that your correct choice would be the one I've attached.
Answer:




Step-by-step explanation:
The probability mass function P(X = x) is the probability that X happens x times.
When n trials happen, for each
, the probability mass function is given by:

In which p is the probability that the event happens.
is the permutation of n elements with x repetitions(when there are multiple events happening(like one passes and two not passing)). It can be calculated by the following formula:

The sum of all P(X=x) must be 1.
In this problem
We have 3 trials, so 
The probability that a wafer pass a test is 0.7, so 
Determine the probability mass function of the number of wafers from a lot that pass the test.



