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3 years ago

Write the following as a mathematical expression

Mathematics

1 answer:

andrey2020 [161]3 years ago

3 0

The answer to that problem si 6-25+2x

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Find highest common factor 12 & 20

eimsori [14]

It's 4. The factors of 12 are: 1,2,3,4,6,12. The factors of 20 are: 1,2,4,5,10,20.

5 0

3 years ago

Read 2 more answers

Mukat has five times as many book as usha.If mukat gave 16 books to usha,they each would have the same number.how many books did

vladimir1956 [14]

Mukat gets 40, Usha gets 8

Step-by-step explanation:

Mukat = 5 × Usha

After Mukat gives Usha 16 books ,Usha gets (16 + initial number of books) and Mukat gets (5 × Usha - 16)

Then Mukat = final number of books for Usha

5 × Usha - 16 = Usha + 16

(5 × Usha ) - Usha = 16+16

4 × Usha = 32

Usha = 8 i.e her number of books.

Mukat = 5×8=40.

I HOPE IT'S OK

6 0

3 years ago

2x + 3x + 5 =<br><br>I need the answer asap

madam [21]

In simplified form it is 5x+5

4 0

3 years ago

Can somebody please help me with this ?

mrs_skeptik [129]

Domain is the values of y.
Plug the x values in the equation to find the corresponding y values:
when x=0, y=3
when x=2, y=-1
when x=-6, y=15
so the answer is D

6 0

3 years ago

Fifteen people have been exposed to a particular disease. Each one independently has a 40% chance of contracting the disease. A

valina [46]

Answer: e. .0950

Step-by-step explanation:

Let X be the number of people that can be cure from disease.

Since each people independently has a 40% chance of contracting the disease.

So , $X\sim Binomial(n=15,p=0.40)$

A hospital has the capacity to handle at most 8 cases of the disease.

Binomial distribution formula : $P(X=x)= ^nC_xp^x(1-p)^{n-x}$

Then , the probability that the hospital’s capacity will be exceeded

$P(X>8)=1-P(X\leq8)\\\\=1-0.905\ \ [\text{Using Binomial distribution table for n=15 , x=8 and p=0.4.}]$

$=0.095$

Hence, the probability that the hospital’s capacity will be exceeded is e. .0950.

Thus , the correct option is e. .0950.

8 0

3 years ago