(x-3) *squared* + (y + 2) *squared* = 6
Answer:
It's d. -4x^2 + 2x + 2.
Step-by-step explanation:
-4x^2 + 2x + 2.
------------------------
6x + 3 )-24x^3 + 0x^2 + 18x + 6
-24x^3 - 12x^2
--------------------
12x^2 + 18x
12x^2 + 6x
--------------
12x + 6
12x + 6
The total of two whole numbers one after another is 33. for example 10 + 11 (two consecutive integers) = 21
Answer:
4p+3
Step-by-step explanation:
Because 4 has the variable p next to it, 4 can not be the same as 6 or 3 because they are whole numbers. So the only thing you can do here is 6-3, which is 3.
