Answer:
Step-by-step explanation:
At first,
Let start writing the squares of number 0 to 10,
0²=0
1²=1
2²=4
3²=9
4²=16
5²=25
6²=36
7²=49
8²=64
9²=81
10²=100
Now,
According to your question,
- The two numbers should be square numbers
- They should be greater than 1.
- Their sum should be 100.
Hence, your given conditions matches with the numbers 64 and 36.
Therefore, the numbers are 64 and 36.
- 64 and 36 are greater than 1.
- 64 is a square of 8 and 36 is the square of 6.
- 64+36=100
1/3x + y = 4....subtract 1/3x from both sides
y = -1/3x + 4 <===
A^2+b^2=c^2
24^2+b^2=26^2
576+b^2=676
-576. -576
b^2=100
Answer: x= -3 11/20 Decimal form: x=-3.55
Step-by-step explanation:
