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Lena [83]
3 years ago
15

A pair of fair dice is rolled. Let E denote the event that the number falling uppermost on the first die is 2, and let F denote

the event that the sum of the numbers falling uppermost is 8. (Round your answers to three decimal places.)
(a) Compute P(F).
(b) Compute P(E ∩ F).
(c) Compute P(F | E).
(d) Compute P(E).
Mathematics
1 answer:
satela [25.4K]3 years ago
4 0

First of all, note that there are 36 possible outcomes (all the numbers from 1 to 6 from the first die, combined with all the numbers from 1 to 6 from the second die).

a. Out of these 36 outcomes, the only ways to get 8 as sum are: (2, 6), (3, 5), (4, 4), (5, 3), (6, 2). There are 5 favourable cases over 36 possible cases, so the probability is 5/36.

b. We want to get 8 as sum, and the first die must be a 2. Out of the five pairs we got before, only the first satisfies this request, so the probability is 1/36

c. Knowing that the first die was a 2, we have 6 possible outcomes:

The second die rolls a 1, for a total of 3.

The second die rolls a 2, for a total of 4.

The second die rolls a 3, for a total of 5.

The second die rolls a 4, for a total of 6.

The second die rolls a 5, for a total of 7.

The second die rolls a 6, for a total of 8.

So, there is 1 favourable outcome out of 6 possible outcomes, so the probability is 1/6

d. The die is fair, so every number occurs with probability 1/6.

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6 0
3 years ago
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When a distribution is mound-shaped symmetrical, what is the general relationship among the values of the mean, median, and mode
yuradex [85]

Answer:

The mean, median, and mode are approximately equal.

Step-by-step explanation:

The mean, median, and mode are <em>central tendency measures</em> in a distribution. That is, they are measures that correspond to a value that represents, roughly speaking, "the center" of the data distribution.

In the case of a <em>normal distribution</em>, these measures are located at the same point (i.e., mean = median = mode) and the values for this type of distribution are symmetrically distributed above and below the mean (mean = median = mode).

When a <em>distribution is not symmetrical</em>, we say it is <em>skewed</em>. The skewness is a measure of the <em>asymmetry</em> of the distribution. In this case, <em>the mean, median and mode are not the same</em>, and we have different possibilities as the mentioned in the question: the mean is less than the median and the mode (<em>negative skew</em>), or greater than them (<em>positive skew</em>), or approximately equal than the median but much greater than the mode (a variation of a <em>positive skew</em> case).  

In the case of the normal distribution, the skewness is 0 (zero).

Therefore, in the case of a <em>mound-shaped symmetrical distribution</em>, it resembles the <em>normal distribution</em> and, as a result, it has similar characteristics for the mean, the median, and the mode, that is, <em>they are all approximately equal</em>. So, <em>the </em><em>general</em><em> relationship among the values for these central tendency measures is that they are all approximately equal for mound-shaped symmetrical distributions, </em>considering they have similar characteristics of the <em>normal distribution</em>, which is also a mound-shaped symmetrical distribution (as well as the t-student distribution).

5 0
3 years ago
If x° – 7x2 + kx + 15 is exactly divisible by (x – 3), then find the value of k.​
faltersainse [42]

Answer:

k=4

Step-by-step explanation:

3 0
2 years ago
4. Which of the following lines is perpendicular to y = -2X + 8?
Alenkinab [10]

For this case we have to by definition, if two lines are perpendicular then the product of its slopes is -1.

That is to say:

m_ {1} * m_ {2} = - 1

We have the following equation:

y = -2x + 8

So:

m_ {1} = - 2

Thus:

m_ {2} = \frac {-1} {m_ {1}}\\m_ {2} = \frac {-1} {- 2}\\m = \frac {1}{2}

Thus, a line perpendicular to the given line must have slope m = \frac {1} {2}.

Option A:

x + 2y = 8\\2y = -x + 8\\y = - \frac {1} {2} x + 4

It is not perpendicular!

Option B:

x-2y = 6\\2y = x-6\\y = \frac {1} {2} x-3

If it is perpendicular!

Option C:

2x + y = 4\\y = -2x + 4

It is not perpendicular!

Option D:

2x-y = 1\\y = 2x-1

It is not perpendicular!

The correct option is option B

ANswer:

Option B

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3 years ago
What is the HCF of 48 &amp; 72​
Masja [62]

Step-by-step explanation:

Factors of 72

= 2 x 36

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= 2 x 2 x 2 x 9

= 2 x 2 x 2 x 3 x 3

Factors of 48

= 2 x 24

= 2 x 2 x 12

= 2 x 2 x 2 x 6

= 2 x 2 x 2 x 2 x 3

Common Factors = 2 x 2 x 2 x 3

HCF = 24

Ans : 24

I hope It's helpful!!

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2 years ago
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