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SSSSS [86.1K]
3 years ago
8

Answer to this problem

Mathematics
2 answers:
evablogger [386]3 years ago
4 0
The answer is b) 2.622x10^14
julia-pushkina [17]3 years ago
4 0
Ans wer is b either use the calculator or multiple 3.8 and 6.9 first and then add exponents on top of 10

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A train traveling at a constant speed takes a passenger from Deer Lake to Liberty, stopping first at Summerville and next at Cyp
nasty-shy [4]
Deer Lake - Summerville - Cypress - Liberty
Deer Lake to Summerville is 3
Summerville to Cypress is 1
Cypress to Liberty is 2
So if the entire trip is 360 miles, then you will take 3+1+2=6.
So from Deer Lake to Cypress, it would be 3+1=4.
So 4/6.
360÷6=60
Therefore 60×4=
240 Miles from Deer Lake to Cypress!
8 0
3 years ago
Read 2 more answers
Q1.Simplify:
solniwko [45]

\textbf{(i)}\\\\\{1^3 +2^3 \} \times \left(\dfrac 13 \right)^2\\\\=(1+8) \left(\dfrac 19 \right)\\\\=9\left(\dfrac 19 \right)\\\\=1\\\\

\textbf{(ii)}\\\\\{5^{-1}\times 4^{-1}\}^2\\\\=\left(5^{-1} \right)^2 \times \left(4^{-1} \right)^2~~~~~~~~~~~;[(ab)^m = a^mb^m]\\\\=5^{-2}\times 4^{-2}~~~~~~~~~~~~~~~~~~~~;[(a^m)^n = a^{mn}]\\\\=\dfrac 1{5^2} \times \dfrac 1{4^2}~~~~~~~~~~~~~~~~~~~~~~;\left[a^{-m} = \dfrac 1{a^m},~ a\neq 0 \right]\\\\=\dfrac{1}{400}\\\\=0.0025\\\\

\textbf{(iii)}\\\\\left\{ \left(\dfrac 13 \right)^{-2}  \times \left( \dfrac 12 \right)^{-2}\right\}\div \left(\dfrac 14 \right)^{-3}\\\\\\=\left( \dfrac 13 \times \dfrac 12 \right)^{-2} \div\left(4^{-1}\right)^{-3}\\\\\\=\left(\dfrac 16 \right)^{-2} \div 4^3\\\\\\=\left(6^{-1} \right)^{-2}\div 4^3\\\\\\=6^2 \div 4^3\\\\\\=36\div 64\\\\\\=\dfrac{9}{16}\\\\\\=0.5625

6 0
2 years ago
Read 2 more answers
Complete #2 for me and show proof , will give brainliest to whose right .​
Stells [14]

Answer:

<u>X</u> <u>Y</u> <u>(</u><u>X,</u><u>Y)</u>

-4 14. (-4,14)

-3 12. (-3,12)

-2 10. (-2,10)

-1 8. (-1,8)

0 6 (0,6)

1 4. (1,4)

2 2. (2,2)

4 0
2 years ago
121-y=197 Solve for y
netineya [11]

Answer:

-76

Step-by-step explanation:

121 - y = 197

-121        -121

-y = 76

*-1   *-1

y = -76

4 0
2 years ago
All the edges of a regular square pyramid have length 8.
Aliun [14]

Answer:

  A) (256/3)√2 ≈ 120.68 units³

  B) 64√3 ≈ 110.85 units²

  C 64(1+√3) ≈ 174.85 units²

Step-by-step explanation:

The dimensions used in the usual formulas for area and volume are not given, so it can work reasonably well to start by finding them.

Each face is an equilateral triangle with side length 8, so the slant height is the altitude of that triangle: 8(√3/2) = 4√3.

The height of the pyramid is the vertical leg of a right triangle with hypotenuse equal to the slant height (4√3) and horizontal leg equal to half the base side length. The height is found from the Pythagorean theorem:

  a² +b² = c²

  b = √(c² -a²) = √((4√3)² -4²) = 4√2

The pyramid with all sides of length 8 has height 4√2 and slant height 4√3.

__

<h3>A)</h3>

The volume is ...

  V = 1/3s²h . . . . . . where s is the side length, and h is the height

  V = 1/3(8²)(4√2) = (256/3)√2 ≈ 120.68 . . . . cubic units

__

<h3>B)</h3>

The lateral area is the total area of the 4 triangular faces, so is ...

  LA = 4(1/2)(bh) = 2(8)(4√3) = 64√3 ≈ 110.85 . . . . square units

h is the slant height in this formula

__

<h3>C)</h3>

The total surface area is the sum of the base area and the lateral area. The base area is the square of the side length.

  SA = 8² +64√3 = 64(1+√3) ≈ 174.85 . . . . square units

7 0
2 years ago
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