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Gnesinka [82]
2 years ago
11

Q1.Simplify:

Mathematics
2 answers:
solniwko [45]2 years ago
6 0

\textbf{(i)}\\\\\{1^3 +2^3 \} \times \left(\dfrac 13 \right)^2\\\\=(1+8) \left(\dfrac 19 \right)\\\\=9\left(\dfrac 19 \right)\\\\=1\\\\

\textbf{(ii)}\\\\\{5^{-1}\times 4^{-1}\}^2\\\\=\left(5^{-1} \right)^2 \times \left(4^{-1} \right)^2~~~~~~~~~~~;[(ab)^m = a^mb^m]\\\\=5^{-2}\times 4^{-2}~~~~~~~~~~~~~~~~~~~~;[(a^m)^n = a^{mn}]\\\\=\dfrac 1{5^2} \times \dfrac 1{4^2}~~~~~~~~~~~~~~~~~~~~~~;\left[a^{-m} = \dfrac 1{a^m},~ a\neq 0 \right]\\\\=\dfrac{1}{400}\\\\=0.0025\\\\

\textbf{(iii)}\\\\\left\{ \left(\dfrac 13 \right)^{-2}  \times \left( \dfrac 12 \right)^{-2}\right\}\div \left(\dfrac 14 \right)^{-3}\\\\\\=\left( \dfrac 13 \times \dfrac 12 \right)^{-2} \div\left(4^{-1}\right)^{-3}\\\\\\=\left(\dfrac 16 \right)^{-2} \div 4^3\\\\\\=\left(6^{-1} \right)^{-2}\div 4^3\\\\\\=6^2 \div 4^3\\\\\\=36\div 64\\\\\\=\dfrac{9}{16}\\\\\\=0.5625

Ivanshal [37]2 years ago
4 0

\purple{\maltese}\large\underline{\underline{\red{\sf\:\: Question :}}} \\  \\

Q1.Simplify:

\\  \sf \: 1) \:  \:  \: ( \: 1  ^{3}  +2 ^{3} \: ) \: × {\bigg( \frac{1}{3}  \bigg) }^{2}  \\

\sf \: 2) \:  \:  \: {{( \:  \: 5 ^{ - 1} ×4^{ - 1} } } \: ) \: ^{2}   \\

\sf \: 3) \:  \:  \:  \bigg(\bigg( \frac{1}{3}\bigg) ^{-1}×\bigg( \frac{1}{2} \bigg)^{-2} \bigg)÷\bigg( \frac{1}{4} \bigg)^{-3} \\\\

\\\purple{\maltese}\large\underline{\underline{\red{\sf\:\: Solution :}}} \\  \\

\\  \bf \: 1) \:  \:  \: ( \: 1  ^{3}  +2 ^{3} \: ) \: × {\bigg( \frac{1}{3}  \bigg) }^{2}   \\

\\   \sf \implies\:\:  \:  \: ( \: 1  ^{3}  +2 ^{3} \: ) \: × {\bigg( \frac{1}{3}  \bigg) }^{2}

\\   \sf \implies\:\:  \:  \: ( \: 1   + 8\: ) \: × {\bigg( \frac{1}{3}  \bigg) }^{2}

\\   \sf \implies\:\:  \:  \: ( \: 1   + 8\: ) \: × {\bigg( \frac{1}{9}  \bigg) }

\\   \sf \implies\:\:  \:  \: ( \: 9\: ) \: × {\bigg( \frac{1}{9}  \bigg) }

\\   \sf \implies\:\:  \:  \: ( \:  \cancel{9}\: ) \: × {\bigg( \frac{1}{\cancel{9}}  \bigg) }

\\   \sf \implies\:\:  \:  \: 1

\implies\sf \underline{ \boxed{\sf \: \:  \:  \: 1 \:  \:  \: }}  \:  \: \bigstar

\\\\\qquad\rule{150pt}{2pt}\\\\

\bf \: 2) \:  \:  \: {{( \:  \: 5 ^{ - 1} ×4^{ - 1} } } \: ) \: ^{2}   \\

\\   \sf \implies\:\:  \:  \: {{( \:  \: 5 ^{ - 1} ×4^{ - 1} } } \: ) \: ^{2}  \\

\\   \sf \implies\:\:  \:  \: {{ {\bigg( \:  \:  \frac{1}{5}  × \frac{1}{4}  } } \: \bigg) } ^{2}  \\

\\   \sf \implies\:\:  \:  \: {{ {\bigg( \:  \:  \frac{1}{20}    } } \: \bigg) } ^{2}  \\

\\   \sf \implies\:\:  \:  \: {{ {\bigg( \:  \:  \frac{1}{400}    } } \: \bigg) } \\

\implies\sf \underline{ \boxed{\sf \: \:  \:  \: \frac{1}{400} \:  \:  \: }}  \:  \: \bigstar \\  \\

\\\\\qquad\rule{150pt}{2pt}\\\\

\\ \bf \: 3) \:  \:  \:  \bigg(\bigg( \frac{1}{3}\bigg) ^{-1}×\bigg( \frac{1}{2} \bigg)^{-2} \bigg)÷\bigg( \frac{1}{4} \bigg)^{-3} \\

\\   \sf \implies\:\:  \:  \: \bigg(\bigg( \frac{1}{3}\bigg) ^{-1}×\bigg( \frac{1}{2} \bigg)^{-2} \bigg)÷\bigg( \frac{1}{4} \bigg)^{-3}\\

\\   \sf \implies\:\:  \:  \:(\:\: 3^{2}- 2^{3} \:\:)÷4^{3}\\

\\   \sf \implies\:\:  \:  \:(\:\: 27- 8\:\:)÷64\\

\\   \sf \implies\:\:  \:  \:19÷64\\

\\   \sf \implies\:\:  \:  \:\frac{19}{64}\\ \\

\implies\sf \underline{ \boxed{\sf \: \:  \:  \: \frac{19}{64} \:  \:  \: }}  \:  \: \bigstar \\  \\

\\\\\qquad\rule{150pt}{2pt}\\\\

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