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alina1380 [7]
3 years ago
11

the pattern blocks in a box are quadrilateral except for one. What shape could the block be that is not a quadrilateral be

Mathematics
1 answer:
Ierofanga [76]3 years ago
7 0
In 2 dimensions, triangles and all polygons with 5 or more sides (pentagons, hexagons, heptagons etc); also, circles, ellipses, cycloids, irregular shapes. Theses are non quadrilateral shapes
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What's 1/3 of $19.95
ki77a [65]
Answer: 6.65

Explanation: 1995/3= 6.65
7 0
3 years ago
Read 2 more answers
Simplify the expression. tan(sin^−1 x)
Blizzard [7]
If you're using the app, try seeing this answer through your browser:  brainly.com/question/2799412

_______________


Let  \mathsf{\theta=sin^{-1}(x)\qquad\qquad-\dfrac{\pi}{2}\ \textless \ \theta\ \textless \ \dfrac{\pi}{2}.}

(that is the range of the inverse sine function).


So,

\mathsf{sin\,\theta=sin\!\left[sin^{-1}(x)\right]}\\\\ \mathsf{sin\,\theta=x\qquad\quad(i)}


Square both sides:

\mathsf{sin^2\,\theta=x^2\qquad\qquad(but~sin^2\,\theta=1-cos^2\,\theta)}\\\\ \mathsf{1-cos^2\,\theta=x^2}\\\\ \mathsf{1-x^2=cos^2\,\theta}\\\\ \mathsf{cos^2\,\theta=1-x^2}


Since \mathsf{-\,\dfrac{\pi}{2}\ \textless \ \theta\ \textless \ \dfrac{\pi}{2},} then \mathsf{cos\,\theta} is positive. So take the positive square root and you get

\mathsf{cos\,\theta=\sqrt{1-x^2}\qquad\quad(ii)}


Then,

\mathsf{tan\,\theta=\dfrac{sin\,\theta}{cos\,\theta}}\\\\\\ \mathsf{tan\,\theta=\dfrac{x}{\sqrt{1-x^2}}}\\\\\\\\ \therefore~~\mathsf{tan\!\left[sin^{-1}(x)\right]=\dfrac{x}{\sqrt{1-x^2}}\qquad\qquad -1\ \textless \ x\ \textless \ 1.}


I hope this helps. =)


Tags:  <em>inverse trigonometric function sin tan arcsin trigonometry</em>

3 0
3 years ago
Read 2 more answers
What are reasons A,B,and C in the proof?
Vlad [161]

Answer:

Option D is correct.

Explanation:

Commutative Property of Multiplication define that two numbers can be multiplied in any order.

i.e a\times b =b \times a

Distributive property of multiplication states that when a number is multiplied by the sum of two numbers i.e, the first number can be distributed to both of those numbers and multiplied by each of them separately.

a \times (b+c) = a\times b+ a\times c

Associative property of multiplication states that multiplication allows us to group factors in different ways to get the same product.

Given:

A = ( 4\times 3) + (2 \times 4 )= ( 4\times 3) + (4 \times 2 )

B = 4 \times ( 3+2)

C = 4 \times 5

then;

( 4\times 3) + (2 \times 4 )

Using Commutative property of Multiplication we can write 2 \times 4 = 4 \times 2 then we have;

( 4\times 3) + (2 \times 4 ) = ( 4\times 3) + (4 \times 2 )

Using Distributive property of multiplication;

( 4\times 3) + (4 \times 2 ) = 4 \times ( 3+2)

by using associative property of multiplication ,

4 \times (3+2) = 4 \times 5

Therefore, the reasons  for A , B and C in this proof are;

A.commutative property of multiplication

B. distributive property

C. associative property of multiplication



6 0
4 years ago
Hey guys! I am having trouble with this question and would love it if someone would explain to me step-by-step how to get the an
Lady_Fox [76]

Answer:

Sorry if my hand writing is bad. I didnt have a calculator for c so idk what it is

5 0
3 years ago
Maria is standing next to a tree. The tree cast a shadow that is 5.4 ft long. The angle formed from the sun hitting the tree and
jenyasd209 [6]
Your answer is 27.0 because to get your answer, you need to multiply 5.4x5


6 0
3 years ago
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