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topjm [15]
3 years ago
5

Given the sequence 5, -10, 20, -40, the next two numbers in the sequence are 80 and -160. true false

Mathematics
1 answer:
jarptica [38.1K]3 years ago
6 0
It is true because every term is the previous term multiplied by -2. So, -40 x -2 = 80, 80 x -2 = -160
You might be interested in
How many terms are in the arithmetic sequence 9, 2, −5, . . . , −187?
Fantom [35]
9, 2, -5... so is going down by 7 each time, meaning the "common difference" is -7.

\bf n^{th}\textit{ term of an arithmetic sequence}\\\\
a_n=a_1+(n-1)d\qquad 
\begin{cases}
n=n^{th}\ term\\
a_1=\textit{first term's value}\\
d=\textit{common difference}\\
----------\\
a_1=9\\
d=-7\\
a_n=-187
\end{cases}
\\\\\\
-187=9+(n-1)(-7)\implies -187=9-7n+7
\\\\\\
7n=9+7+187\implies 7n=203\implies n=\cfrac{203}{7}\implies \boxed{n=29}
4 0
3 years ago
The difference between the roots of the quadratic equation x2 -14x +q =0 is 6. Find q
Irina-Kira [14]

9514 1404 393

Answer:

  q = 40

Step-by-step explanation:

When the quadratic has roots p and r, it can be factored as ...

  (x -p)(x -r) = x² -(p+r)x +pr

So, the sum of the roots is 14, and their difference is 6. This lets us find the roots from ...

  p + r = 14

  p - r = 6

  2p = 20 . . . add the two equations

  p = 10

  r = 14 -p = 4

The value of interest is then ...

  q = pr = (10)(4)

  q = 40

__

The graph shows the roots to be 4 and 10, as we found.

3 0
3 years ago
Let the function f be defined as f(x)= 5x^2 - 7(4x+3). What is the value of f(3)
Katen [24]

Answer:

f(x) = -60 is your answer

Step-by-step explanation:

Plug in 3 for x

f(x) = 5x² - 7(4x + 3)

f(x) = 5(3²) - 7(4(3) + 3)

Follow PEMDAS. First, solve the parenthesis

3² = 9

4(3) + 3 = 12 + 3 = 15

f(x) = 5(9) - 7(15)

Multiply

f(x) = 45 - 105

Simplify. Subtract

f(x) = 45 - 105

f(x) = -60

f(x) = -60 is your answer

~

4 0
3 years ago
Which of the following (-1,8) and (5,-2) are the distance of the line segment
olganol [36]

The formula of a distance between two points:

d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}

We have the points (-1, 8) and (5, -2). Substitute:

d=\sqrt{(5-(-1))^2+(-2-8)^2}=\sqrt{6^2+(-10)^2}=\sqrt{36+100}=\sqrt{136}\\\\=\sqrt{4\cdot34}=\sqrt4\cdot\sqrt{34}=\boxed{2\sqrt{34}}

8 0
3 years ago
Kaytaytay talk here
DochEvi [55]
Integers I believe :) hope this helps
5 0
2 years ago
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