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svp [43]
3 years ago
5

P/3=12

Mathematics
1 answer:
guajiro [1.7K]3 years ago
7 0
I think it would be b as 12x3=36 and then 36/3=12 I might be wrong tho
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Mel used partial quotients to find the quotient of 378 divided by 3.What could be the partial quotient that Mel found?
Genrish500 [490]

Answer:

The partial quotients are 100, 20 and 6. The quotient is 126.

Step-by-step explanation:

The dividend is 378 and the divisor is 3.

First find the factors of 3, near to 300.

3\times 1=3

3\times 10=30

3\times 100=300

The value 300 is less than 378, so record the partial quotient 100 and subtract 300 from 378. Repeat the same process until the dividend has been zero.

Now the remaining divide is 78.

First find the factors of 3, near to 78.

3\times 20=60

3\times 30=90

Since 90>78, therefore 30 is not a partial quotient. The value 60 is less than 78 , so record the partial quotient 20 and subtract 60 from 78.

Now the remaining divide is 18.

3\times 6=18

The number 6 is a partial quotient.

Therefore  partial quotients are 100, 20 and 6. Add the partial quotient to find quotient.

100+20+6=126

3 0
3 years ago
Name the Solid.
Soloha48 [4]

Answer:

Pyramid

V= 240 m^3

Step-by-step explanation:

The volume of a pyramid is 1/3 the Base times the height.

1/3x(10x8)x9

7 0
2 years ago
Simplify the expression -3(x+3)+4x
Korolek [52]

Answer:

x - 9

Step-by-step explanation:

In this case, "simplify" directs that you 1) carry out the indicated multiplication and 2) combine like terms.

-3(x+3)+4x = -3x - 9 + 4x = x - 9

8 0
3 years ago
Read 2 more answers
72÷6374<br><img src="https://tex.z-dn.net/?f=72%20%5Cdiv%206374" id="TexFormula1" title="72 \div 6374" alt="72 \div 6374" align=
Ivan
72 divided by 6374 is equal to 0.0113

Hope it helps :)
6 0
3 years ago
What are these negative fractions converted to positive ones (I suck at math so I need an explanation): -5/6, -7 3/8, -3/11
Paraphin [41]

Answer:

multiply each by -1

-5/6 x -1 = 5/6

-7 3/8 x -1 = 7 3/8

-3/11 x -1 = 3/11

Step-by-step explanation:

6 0
2 years ago
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