One car travel 56 miles per hour and another travels 31 miles per hour. If they start from the same place at the same time and t

Question

3 years ago

10

ravel in the same direction, after how many hours will the faster car be 75 miles ahead of the slower car?

1 answer:

Vitek1552 [10] · Answer 1 · 2021-11-29T10:18:40+03:00

After 3 hours, the faster car will be 75 miles ahead of the slower car.

Step-by-step explanation:

Given,

Speed of first car = 56 miles per hour

Speed of second car = 31 miles per hour

Let,

x be the number of hours.

Distance covered by first car = Speed * time = 56x

Distance covered by second car = 31x

According to given statement;

Difference between distance covered by both cars = 75 miles

Distance of faster car - Distance of slower car = 75 miles

$56x-31x=75\\25x=75$

Dividing both sides by 25

$\frac{25x}{25}=\frac{75}{25}\\x=3$

After 3 hours, the faster car will be 75 miles ahead of the slower car.

Keywords: subtraction, division

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