1. No
2. No
3. Yes
4. No, it’s actually 24j -36
Let c represent the weight of cashews and p the weight of pecans.
Then c + 10 = total weight of the nut mixture.
An equation for the value of the mixture follows:
$1.50(10 lb) + $0.75c = (c+10)($1.00)
Solve this equation for c: 15 + .75c = c + 10. Subtract .75c from both sides:
15 = 1c - 0.75c + 10. Then 5=0.25c, and c = 5/0.25, or 20.
Need 20 lb of cashews.
Check: the pecans weigh 10 lb and are worth $1.50 per lb, so the total value of the pecans is $15. The total value of the cashews is (20 lb)($0.75/lb), or $15. Does (20 lb + 10 lb)($1/lb) = $15 + $15? Yes. So c= 20 lb is correct.
Use PEMDAS with the first 3.
a. 3×(6÷5)
3×(1.2) [Parenthesis first]
3.6. [then multiply]
b. 3÷(5×6)
3÷(30) [Parenthesis first]
.1 [then divide]
c. (3×6)÷5
(18)÷5 [Parenthesis first]
3.6 [then divide]
d. 3×6÷5
18÷5 [Left to right]
3.6 [then divide]
g - 3/7 = 2/7 is an equation.
