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olya-2409 [2.1K]
3 years ago
8

Who is Lonely at the current moment....and not busy?

Mathematics
1 answer:
sergejj [24]3 years ago
5 0

hAHAHahah haHaHrwahrahweha

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Find the local maximum and minimum values and saddle point(s) of the function. If you have three-dimensional graphing software,
vichka [17]

Answer:

A(-1,0) is a local maximum point.

B(-1,0)  is a saddle point

C(3,0)  is a saddle point

D(3,2) is a local minimum point.

Step-by-step explanation:

The given function is  

f(x,y)=x^3+y^3-3x^2-3y^2-9x

The first partial derivative with respect to x is  

f_x=3x^2-6x-9

The first partial derivative with respect to y is  

f_y=3y^2-6y

We now set each equation to zero to obtain the system of equations;

3x^2-6x-9=0

3y^2-6y=0

Solving the two equations simultaneously, gives;

x=-1,x=3  and y=0,y=2

The critical points are

A(-1,0), B(-1,2),C(3,0),and D(3,2).

Now, we need to calculate the discriminant,

D=f_{xx}(x,y)f_{yy}(x,y)-(f_{xy}(x,y))^2

But, we would have to calculate the second partial derivatives first.

f_{xx}=6x-6

f_{yy}=6y-6

f_{xy}=0

\Rightarrow D=(6x-6)(6y-6)-0^2

\Rightarrow D=(6x-6)(6y-6)

At A(-1,0),

D=(6(-1)-6)(6(0)-6)=72\:>\:0 and f_{xx}=6(-1)-6=-18\:

Hence A(-1,0) is a local maximum point.

See graph

At B(-1,2);

D=(6(-1)-6)(6(2)-6)=-72\:

Hence, B(-1,0) is neither a local maximum or a local minimum point.

This is a saddle point.

At C(3,0)

D=(6(3)-6)(6(0)-6)=-72\:

Hence, C(3,0) is neither a local minimum or maximum point. It is a saddle point.

At D(3,2),

D=(6(3)-6)(6(2)-6)=72\:>\:0 and f_{xx}=6(3)-6=12\:>\:0

Hence D(3,2) is a local minimum point.

See graph in attachment.

3 0
3 years ago
The grill was regularly priced at $58, but Jared had a coupon for 25% off. How much money did Jared save by using his coupon?
frosja888 [35]

Answer:

He saves $14.50

Step-by-step explanation:

We can find the discount by multiplying the price by the percentage off

58* .25  = 14.50

He saves $14.50


7 0
3 years ago
Read 2 more answers
Write an algebraic expression to represent the following verbal expression
DaniilM [7]
The answer is B. They are saying to cube the difference therefore you have (x-43) cubed
4 0
3 years ago
Read 2 more answers
Brainest for best answer only 5 mins left show your work
Kamila [148]

Answer:

Step-by-step explanation:

Problem One

Perimeter is in meters not square meters. The equation is

2*(6.8+x) + 2*12.5= 47                Remove the brackets. Combine like terms  

13.6 + 2x + 25 = 47

38.6 + 2x = 47                            Subtract 38.5 from both sides

2x = 47 - 38.6  

2x = 8.4                                      Divide by 2

x = 4.2

Answer D

Problem 2

This problem is asking that you calculate the perimeter of a swimming pool.

The two semicircles on the ends make a whole circle.

The diameter of the semicircles is obtained from the difference of the two given lengths.

The rectangle has a length of 12. The length of the rectangle and the 2 semicircles is 16. The difference is 4. You could divide this by 2 to get the radius. I would just leave it as the diameter.

So the perimeter is pi*d + 2 * 12 [there are 2 lengths]

Perimeter = 4*pi + 24

Perimeter = 12.56 + 24

Perimeter = 36.56

Answer A

Problem 3

This is the circle inside the square.

The radius of the circle = 9

The diameter of the circle and the length of square's side = 2*9 = 18

The area of the square = s^2  where s = 18

The area of the square = 18^2 = 324

The area of the circle = pi * 9^2 = 3.24 * 81 = 251.34

The area of the Shaded area = 324 - 251.34 = 69.66

Answer C

Problem 4

b1 = 5

b2 = 11.5

h = 4.5

Formula

Area = (b1 + b2 ) * 4.5/2

Area =  (5 + 11.5) * 4.5 /2

Area = 16.5 * 4.5 / 2

Area = 74.25/2

Area = 37.125

Answer D

5 0
3 years ago
What is the reference angle in radians for 1380°?
ad-work [718]
Hello there.

What is the reference angle in radians for 1380°?

Answer: 60
8 0
3 years ago
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