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castortr0y [4]
4 years ago
8

I am doing exponents. My first problem is y5 ÷ y3 , y ¥0

Mathematics
1 answer:
Mrrafil [7]4 years ago
5 0
Y^5 : y^3 --> divisão de potências de mesma base...
repete a base e diminui os expoentes, ou seja, 
y^5 : y^3 = y^(5-3) = y^2
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4 0
4 years ago
(7t-2)-(-3+1)=-3(1-3t) how do you do this?
Sergeu [11.5K]
<h2>Greetings!</h2>

Answer:

t = \frac{3}{2}

Step-by-step explanation:

First, you need to complete the -3 + 1 and then expand the brackets

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7t -2 - (-2) = -3(1 - 3t)

Now expant the -3(1 - 3t) bracket

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Divide both sides by 2:

t = \frac{3}{2}

So the value of t is \frac{3}{2}


<h2>Hope this helps!</h2>
6 0
4 years ago
The sum of a number and seven is fifty-five. Find the number
Sonbull [250]
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That's a sideways parabola,

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3 years ago
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