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abruzzese [7]
4 years ago
9

There are 24 fish in an aquarium. If 1/8 of them are tetras, and 2/3 of the remaining fish are guppies, how many guppies are in

the aquarium?
Mathematics
1 answer:
kiruha [24]4 years ago
8 0

Answer:

14 guppies

Step-by-step explanation:

1/8th of 24 is 3 which leaves 21 remaining

2/3 of 21 is 14 as each third is 7

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Simplest form 816/10
Katyanochek1 [597]

Answer: The answer is 408/5 , as a mixed number = ( 81 3/5)

~hope this helps!~

Step-by-step explanation:

4 0
3 years ago
Hurry I need help!!!!
Gekata [30.6K]
Answer = A

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3 0
3 years ago
Read 2 more answers
Which of the following angles is coterminal with one that measures 98 degrees
polet [3.4K]

Answer:

See below

Step-by-step explanation:

You have not provided the options.

But I will explain how you can work it.

Coterminal angles are two or more angles that have the same terminal side in standard.

If you want to find an angle that is coterminal with 98°, you keep adding or subtracting 360°.

98  + 360 = 458 \\ 98 + 2 \times 360 = 818

98 - 360 =  - 262

Therefore 488°, 818°, -262° are examples of angles that are coterminal with 98°

6 0
3 years ago
10.9 as a fraction or mixed number
strojnjashka [21]
The answer is 10 9/10 hope this helped
7 0
3 years ago
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A bird species in danger of extinction has a population that is decreasing exponentially (A = A0e^kt). Five years ago, the popul
Natalija [7]

Answer:

It'll take approximately 34 years from today.

Step-by-step explanation:

in order to solve this problem we first need to find the rate of change, "k", to do that we will use the given information where the population was 1400 five years ago and its now 1000. Applying this data to the equation gives us:

A = A_0*e^{k*t}\\1000 = 1400*e^{5*k}\\1400*e^{5*k} = 1000\\e^{5*k} = \frac{1000}{1400}\\ln(e^{5*k}) = ln(\frac{1000}{1400})\\5*k = ln(1000) - ln(1400) \\k = \frac{ln(1000) - ln(1400)}{5} = -0.06729

We now know the value for "k", we can estimate how many years it will take for the bird population to dip below 100. We have:

100 = 1000*e^{-0.06729*t}\\e^{-0.06729*t} = \frac{100}{1000}\\ln(e^{-0.06729*t} = \frac{1}{10}\\-0.06729*t = ln(0.1)\\t = -\frac{ln(0.1)}{0.06729} = 34.22

It'll take approximately 34 years from today.

8 0
4 years ago
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