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Lisa [10]
3 years ago
7

For the following code, how many times would the for loop execute? String str = ("Ben and Jerry's ice cream is great."); String[

] tokens = str.split(" "); for (String s : tokens) System.out.println(s);
A. 1
B. 3
C. 5
D. 7
Computers and Technology
1 answer:
Kay [80]3 years ago
3 0

Answer:

D. 7

Explanation:

Given code:

String str = ("Ben and Jerry's ice cream is great.");  

String[] tokens = str.split(" ");  

for (String s : tokens) System.out.println(s);

Splitting the given sentence on space character yields 7 tokens, namely:

Ben , and , Jerry's , ice , cream , is , great.

So the for loop will execute 7 times, once for each token because the loop variable s is assigned an individual token on each iteration.

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Answer:

The statement would be true

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Explanation:

let,  L = is a NFL player

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nfl player who teaches in csu = L^ M                 (this is false every time)

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this would be true because

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There are no players who teach in Csu therefore if we say they all have tattoos statement would be true.

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Write a program that helps a young student learn to make change. Use the random number generator to generate change amounts betw
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Answer:

#include <iostream>

#include <stdlib.h>

using namespace std;

int main()

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srand(time(0));

 

int coins = rand()%99 + 1;

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cout<<"Enter the coins needed to make $0."<<coins<<"?"<<endl<<endl;

int a, b, c, d;

cout<<"Quarters? ";

cin>>a;

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cin>>b;

cout<<"Nickles? ";

cin>>c;

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cin>>d;

 

int quarters = coins/25;

 

coins = coins%25;

 

int dimes = coins/10;

 

coins = coins%10;

 

int nickles = coins/5;

coins = coins%5;

 

int pennies = coins/1;

 

if(((a*25) + (b*10) + (c*5) + (d*1))==temp)

{

cout<<"That's correct"<<endl;

 

if(a!=quarters || b!=dimes || c!=nickles || d!=pennies)

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cout<<"The optimized solution is "<<endl;

}

}

else

{

cout<<"Not correct"<<endl;

cout<<"The solution is "<<endl;

 

}

 

cout<<"\tQuarters: "<<quarters<<endl;

cout<<"\tDimes: "<<dimes<<endl;

cout<<"\tNickles: "<<nickles<<endl;

cout<<"\tPennies: "<<pennies<<endl;

return 0;

}#include <iostream>

#include <stdlib.h>

using namespace std;

int main()

{

srand(time(0));

 

int coins = rand()%99 + 1;

int temp = coins;

cout<<"Enter the coins needed to make $0."<<coins<<"?"<<endl<<endl;

int a, b, c, d;

cout<<"Quarters? ";

cin>>a;

cout<<"Dimes? ";

cin>>b;

cout<<"Nickles? ";

cin>>c;

cout<<"Pennies? ";

cin>>d;

 

int quarters = coins/25;

 

coins = coins%25;

 

int dimes = coins/10;

 

coins = coins%10;

 

int nickles = coins/5;

coins = coins%5;

 

int pennies = coins/1;

 

if(((a*25) + (b*10) + (c*5) + (d*1))==temp)

{

cout<<"That's correct"<<endl;

 

if(a!=quarters || b!=dimes || c!=nickles || d!=pennies)

{

cout<<"The optimized solution is "<<endl;

}

}

else

{

cout<<"Not correct"<<endl;

cout<<"The solution is "<<endl;

 

}

 

cout<<"\tQuarters: "<<quarters<<endl;

cout<<"\tDimes: "<<dimes<<endl;

cout<<"\tNickles: "<<nickles<<endl;

cout<<"\tPennies: "<<pennies<<endl;

return 0;

}

Explanation:

  • Use the built-in rand function to generate a random coin.
  • Get all the required values for quarters, dimes, nickles and pennies and store them in variables.
  • Check if the coins give a value of temp, then answer is correct and the values of user will be added.
  • Optimum solution is displayed  If it does not matches with the optimum solution. Display that the answer is wrong along with solution.
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Answer:

The question is a bit unclear. Are you asking how to add these values in this 2D array?

Explanation:

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Those would be numbers below 1.

Explanation:
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