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Tju [1.3M]
2 years ago
6

Let G = (V, E) be an undirected graph. Design algorithms for the following (in each

Computers and Technology
1 answer:
Degger [83]2 years ago
3 0

Answer:

i think its b if not sorry

Explanation:

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Rr lyrae stars pulsate, but with shorter periods and lower luminosities than cepheids. true false
KIM [24]

True, RR Lyrae stars pulsate, but with shorter periods and lower luminosities than Cepheids.

The pulsation periods of the fundamental-mode RR Lyrae stars range from about 0.3 to 1.0 days (Population II pulsators with longer periods are categorized as type II Cepheids), but the vast majority of them have generations longer than 0.45 days.

<h3>Why do RR Lyrae stars pulsate?</h3>

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To learn more about RR Lyrae, refer

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2 years ago
What study skill is being used when taking a large project and breaking it down into smaller manageable tasks?
Lostsunrise [7]
Not sure but I think it’s called prioritizing
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Write an application that determines whether the first two files are located in the same folder as the third one. The program sh
marissa [1.9K]

Answer:

The program in Python is as follows:

fname1 = input("Filepath 1: ").lower()

fname2 = input("Filepath 2: ").lower()

fname3 = input("Filepath 3: ").lower()

f1dir = ""; f2dir = ""; f3dir = ""

fnamesplit = fname1.split("/")

for i in range(len(fnamesplit)-1):

   f1dir+=fnamesplit[i]+"/"

fnamesplit = fname2.split("/")

for i in range(len(fnamesplit)-1):

   f2dir+=fnamesplit[i]+"/"

fnamesplit = fname3.split("/")

for i in range(len(fnamesplit)-1):

   f3dir+=fnamesplit[i]+"/"

if f1dir == f2dir == f3dir:

   print("Files are in the same folder")

else:

   print("Files are in the different folder")

Explanation:

The next three lines get the file path of the three files

<em>fname1 = input("Filepath 1: ").lower()</em>

<em>fname2 = input("Filepath 2: ").lower()</em>

<em>fname3 = input("Filepath 3: ").lower()</em>

This initializes the directory of the three files to an empty string

f1dir = ""; f2dir = ""; f3dir = ""

This splits file name 1 by "/"

fnamesplit = fname1.split("/")

This iteration gets the directory of file 1 (leaving out the file name)

<em>for i in range(len(fnamesplit)-1):</em>

<em>    f1dir+=fnamesplit[i]+"/"</em>

This splits file name 2 by "/"

fnamesplit = fname2.split("/")

This iteration gets the directory of file 2 (leaving out the file name)

<em>for i in range(len(fnamesplit)-1):</em>

<em>    f2dir+=fnamesplit[i]+"/"</em>

This splits file name 3 by "/"

fnamesplit = fname3.split("/")

This iteration gets the directory of file 3 (leaving out the file name)

<em>for i in range(len(fnamesplit)-1):</em>

<em>    f3dir+=fnamesplit[i]+"/"</em>

This checks if the file directories hold the same value

This is executed, if yes

<em>if f1dir == f2dir == f3dir:</em>

<em>    print("Files are in the same folder")</em>

This is executed, if otherwise

<em>else:</em>

<em>    print("Files are in the different folder")</em>

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3 years ago
Eric would like to have a color textbook that makes it look as if the character in an image is speaking. Which object should he
timurjin [86]

Explanation:

the answer is call out safe or picture

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Briefly explain specialisation?​
Jlenok [28]

Answer:

b

Explanation:

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