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3 years ago

Compare 98 in and 8 ft

2 answers:

8 0

We know that they're 12(in) in a foot.

So, if we were to divide them, we would then get 12 feet, and also 25th of 12(in).

Savatey [412]3 years ago

5 0

Let

$x=98\ in\\y=8\ ft$

we know that

$1\ ft=12\ in$

convert feet to inches

$8\ ft=8*12=96\ in$

Compare the measures

$x=y+2$

therefore

the answer is

the measure of $98\ in$ is $2$ inches greater than the measure of $8\ ft$

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Find the surface area of a sphere with a radius of 8cm

Flauer [41]

The surface area of a sphere is:
$4\pi \: r {}^{2}$
$4 \times 3.14 \times 8$
$100.48 \: cm {}^{2}$

3 0

3 years ago

HURRY please MID CLASS

gladu [14]

Answer:

1) 6/4 or 1 1/2, so you fill in 6 of the lines in the model

2) 8/6 or 1 1/3, so you need to fill in 8 of the lines in the model

Step-by-step explanation:

Hope this helps!

5 0

3 years ago

The price of a television decreased from $275 to $190 during a clearance sale. Solve for the percent of decrease in the price. R

IRINA_888 [86]

Since we know 100% = 100
Take $275 - $190 = $85 , and then use $85 x 100 divided by the amount of $
85 x 100 / 275 = 30.9 Round to the nearest tenths which will equal to 31%. So the answer is B.

6 0

3 years ago

Find the midpoint of diagonal WY.. . Figure WXYZ is shown. W is at 0, 2. X is at 0, 6. Y is at 6, 6. Z is at 6, 2.. . (2, 4). .

Anestetic [448]

Answer:

$(3,4)$

Step-by-step explanation:

we know that

The formula to calculate the coordinates of the midpoint between two points is equal to

$M(\frac{x1+x2}{2},\frac{y1+y2}{2})$

we have that

The coordinates of diagonal WY are

$W(0,2), Y(6,6)$

substitute in the formula to calculate the midpoint

$M(\frac{0+6}{2},\frac{2+6}{2})$

$M(\frac{6}{2},\frac{8}{2})$

$M(3,4)$

3 0

3 years ago

Read 2 more answers

The weights of the fish in a certain lake are normally distributed with a mean of 11 lb and a standard deviation of 6. if 4 fish

Alexus [3.1K]

Since the sample standard deviation is now known, we use the z-score test. The formula is given as:

z= (X – μ) / (s / sqrt(n))

Where,

X = sample mean = 8.6 lb to 14.6 lb

μ = population mean = 11 lb

s = population standard deviation = 6

n = sample size = 4

1st: Calculating for z when x = 8.6 lb

z = (8.6 – 11) / (6 / sqrt4)

z = - 0.8

Using the standard distribution table for z:

Probability (x = 8.6 lb) = 0.2119

2nd: Calculating for z when x = 14.6 lb

z = (14.6 – 11) / (6 / sqrt4)

z = 1.2

Using the standard distribution table for z:

Probability (x = 14.6 lb) = 0.8849

Therefore the probability that the mean weight will be between 8.6 and 14.6 lb:

Probability (8.6 ≤ x ≤ 14.6 ) = 0.8849 - 0.2119

Probability (8.6 ≤ x ≤ 14.6 ) = 0.673 (ANSWER)

8 0

3 years ago