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HACTEHA [7]
3 years ago
14

(03.03 MC) Choose the graph below that correctly represents the equation 2x + 4y = 24. (5 points) Select one: a. line through th

e points 0 comma 6 and 12 comma 0 b. line through the points 0 comma negative 6 and 12 comma 0 c. line through the points 0 comma negative 12 and 6 comma 0 d. line through the points 0 comma 12 and 6 comma 0
Mathematics
2 answers:
mario62 [17]3 years ago
8 0

Answer:

The correct option is A) Line through the point (0,6) and (12,0).

Step-by-step explanation:

Consider the provided equation 2<em>x</em> + 4<em>y</em> = 24.

Substitute <em>x</em> = 0 in the provided equation.

2<em>x</em> + 4<em>y</em> = 24

2(0) + 4<em>y </em>= 24

4<em>y </em>= 24

<em>y </em>= 6

Thus, the points which satisfy the equation is (0,6).

Now, substitute <em>x</em> = 12 in the provided equation.

2<em>x</em> + 4<em>y</em> = 24

2(12) + 4<em>y </em>= 24

24 + 4<em>y </em>= 24

<em>4y </em>= 0

<em>y </em>= 0

Thus, the points which satisfy the equation is (12,0).

Therefore, the correct option is A) Line through the point (0,6) and (12,0).

Mnenie [13.5K]3 years ago
7 0

Answer:

your line goes through both (0,6) and (12,0)

Step-by-step explanation:

Ok so you are describing some lines you see I think:

I see some of these as points you mentioned:

(0,6)  ,  (0,-6)  , (6,0)

So let's see which of these work:

(0,6)?

2(0)+4(6)=24

        24=24

(0,6) does work!

The other point you have listed with (0,6) is (12,0).

Let's try (12,0)

2(12)+4(0)=24

24+0=24

24=24

(12,0) works!

So your line goes through both (0,6) and (12,0)

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When 1,250 Superscript three-fourths is written in simplest radical form, which value remains under the radical?
Dvinal [7]

The value remains under the radical is 8 ⇒ last answer

Step-by-step explanation:

Let us revise how to write the exponent as a radical

  • a^{\frac{m}{n}} can be written as \sqrt[n]{a^{m}}
  • To simplify the radical factorize the base "a" to its prime factors

Example:

  • (54)^{\frac{2}{3}}=\sqrt[3]{(54)^{2}} ,
  • Factorize 54 into prime factors ⇒ 54 = 2 × 3 × 3 × 3 = 2(3)^{3}
  • \sqrt[3]{(54)^{2}}=\sqrt[3]{[2(3^{3}]^{2}}=\sqrt[3]{2^{2}*3^{6}}
  • 2² can not go out the radical because 2 is less than 3 not divisible by 3
  • 3^{6} can go out the radical because 6 is divisible by 3, then divide 6 by 3, so it will be 3² out the radical
  • \sqrt[3]{(54)^{2}}=3^{2}\sqrt[3]{2^{2}}=9\sqrt[3]{4}

Now let us solve your problem

∵ 1250^{\frac{3}{4}}=\sqrt[4]{1250^{3}}

- Factorize 1250 to its prime factors

∵ 1250 = 2 × 5 × 5 × 5 × 5

∴ 1250=2*5^{4}

∴ \sqrt[4]{(2*5^{4})^{3}}=\sqrt[4]{2^{3}*5^{12}}

∵ 2³ can not go out the radical because 3 < 4 and not divisible by it

- 5^{12} can go out the radical because 12 can divided by 4

∵ 12 ÷ 4 = 3

∴ 5^{12} can go out the radical as 5³

∴ \sqrt[4]{1250}=5^{3}\sqrt[4]{2^{3}}

∴ \sqrt[4]{1250}=125\sqrt[4]{8}

∴ The value remains under the radical = 8

The value remains under the radical is 8

Learn more:

You can learn more about the radicals in brainly.com/question/7153188

#LearnwithBrainly

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The only thing i can think would work is 6*7=7*6

42=42
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500 people were surveyed and asked whether had donated food or money to local charities in the past year.  80 had donated food,
SOVA2 [1]
80 + 150 - 45= 185 (take away 45 as that was duplicated in the groups) 
185/500= 0.37
4 0
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What is the distance between the points (18, 39) and (3, 39) in the xy-plane?
nydimaria [60]

Answer:

C. 15 units,

Step-by-step explanation:

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Distance = 18-3 = 15.

8 0
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