Identify an equation in point-slope form for the line perpendicular to y=-1/3x-6 that passes through (–1, 5).
1 answer:
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Given:
A plane is normal to the vector = -2i+5j+k
It contains the point (-10,7,5).
To find:
The component equation of the plane.
Solution:
The equation of plane is
Where, is the point on the plane and
is normal vector.
Normal vector is -2i+5j+k and plane passes through (-10,7,5). So, the equation of the plane is
Therefore, the equation of the plane is .