Answer:
A: P = 41100 - 590t
B: 34610
Step-by-step explanation:
equation = 41100-(41100-36380)/(2011-2003)t
plug it in
41100 - 590(2014-2003)=34610
Part A:
The probability that a normally distributed data with a mean, μ and standard deviation, σ is greater than a given value, a is given by:

Given that the average precipitation in
Toledo, Ohio for the past 7 months is 19.32 inches with a standard deviation of 2.44 inches, the probability that <span>a randomly selected year will have precipitation greater than 18 inches for the first 7 months is given by:

Part B:
</span>The probability that an n randomly selected samples of a normally distributed data with a mean, μ and
standard deviation, σ is greater than a given value, a is given by:

Given that the average precipitation in
Toledo, Ohio for the past 7 months is 19.32 inches with a standard deviation of 2.44 inches, the probability that <span>5 randomly selected years will have precipitation greater than 18 inches for the first 7 months is given by:
</span>
SOLUTION
TO DETERMINE
The degree of the polynomial
CONCEPT TO BE IMPLEMENTED
POLYNOMIAL
Polynomial is a mathematical expression consisting of variables, constants that can be combined using mathematical operations addition, subtraction, multiplication and whole number exponentiation of variables
DEGREE OF A POLYNOMIAL
Degree of a polynomial is defined as the highest power of its variable that appears with nonzero coefficient
When a polynomial has more than one variable, we need to find the degree by adding the exponents of each variable in each term.
EVALUATION
Here the given polynomial is
In the above polynomial variable is z
The highest power of its variable ( z ) that appears with nonzero coefficient is 5
Hence the degree of the polynomial is 5
FINAL ANSWER
The degree of the polynomial is 5
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Learn more from Brainly :-
1. Find the degree of 2020?
brainly.in/question/25939171
2. Write the degree of the given polynomial: 5x³+4x²+7x
Answer:
1/3÷6
1/3 x 1/6
Step-by-step explanation:
You want to get an answer of 1/18, which these equations give.