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3 years ago

I need the answers to these math problems

Mathematics

2 answers:

Sergio039 [100]3 years ago

6 0

6. 6•2-1 = 12-1 = 11
9+2 = 11 11 = 1

7. 9•[8-2-3-(9-8)] 9-8 = 1
8-2-3 = 3 • 9 = 27+1 = 28

8. [7•3-(6+9)]/2= 6+9= 15
7•3 = 21 /2 = 10.5

9. 2•10/5+(7+5)/2= 7+5=12
2•10 = 20/2 = 10+12 = 22

10. 2•6-9-[5-(9-7)] 9-7 = 2
5-2 = 3
2•6= 12-9+3 = 3+3=6

11. 10+10/5-8 = 10/5 = 2
10-8+2= 2+2=4

12. [2-(10-8)]•6+3•5 = 10-8=2
2-2= 0 • 6 = 0+3•5 =15

13. 8/2/(6-4) = 6-4 = 2
8/2/2 = 4/2=2

14. 6[5+(14-8)/3] = 14-8=6 = 5+6/3= 2+5= 7•6 = 42

make sure you always use PEMDAS! those brackets are important too. once you do the problem inside the parentheses you go straight to the problem inside the bracket then move further on. please make brainliest :)!!

mafiozo [28]3 years ago

3 0

5# 25-(2×10)=25-20=5. 7# 9×(8-2-3-1)=9×2=18. 8# (7×3-15)÷2=(21-15)÷2=6÷2=3. 9# 2×10÷5+12÷2=20÷5+12÷2=4+6=10. 10# 2×6-9-(5-2)=2×6-9-3=12-9-3=3-3=0. 11# 10+2-8=12-8=4

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Step-by-step explanation:

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$\implies f(x) =1 \sin (6(x + 0)) + 3$

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