<span>Traveled Downstream a distance of 33 Mi and then came right back. If the speed of the current was 12 mph and the total trip took 3 hours and 40 minutes.
Let S = boat speed in still water then (s + 12) = downstream speed (s -12) = upstream speed
Given Time = 3 hours 40 minutes = 220 minutes = (220/60) h = (11/3) h Time = Distance/Speed
33/(s +12) + 33/(s-12) = 11/3 3{33(s-12) + 33(s +12)} = 11(s+12) (s -12) 99(s -12 + s + 12) = 11(</span> s^{2} + 12 s -12 s -144) 99(2 s) = 11(s^{2} -144) 198 s/11 = (s^{2} -144) 18 s = (s^{2} -144) (s^{2} - 18 s - 144) = 0 s^{2} - 24 s + 6 s -144 =0 s(s- 24) + 6(s -24) =0 (s -24) (s + 6) = 0 s -24 = 0, s + 6 =0 s = 24, s = -6 Answer) s = 24 mph is the average speed of the boat relative to the water.
Answer: 3
Step-by-step explanation:
Answer:
P = 2(2y+3)
P = 30
Step-by-step explanation:
P = 2 (L+W) or P = L + L + W + W
P = 2 (2y+3)
P = 4y+6
Plug in 6 for y.
P = 24+6
P = 30
The change, from the predicted data to the actual data, in the average number of downloads of the application for Company A from the day the application was launched to 4 days after the application was launched would decrease by approximately 244 downloads per day.
The change, from the predicted data to the actual data, in the average number of downloads of the application for Company B from the day the application was launched to 4 days after the application was launched would increase by approximately 174 downloads per day.
Based on this information, Company B made a more accurate prediction of the average number of downloads of the application per day.
