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3 years ago

8

James makes a necklace with beads that are 0.08 meter long Her next necklace will have beads that are 1/10 the size of the beads

of the first necklace

1 answer:

stiks02 [169]3 years ago

7 0

The beads for the next necklace would be .008

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Which of the following represents the graph of f(x)=1/2^x+2

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3 years ago

A television has a length of 56

musickatia [10]

Answer: 65 inches

Step-by-step explanation:

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c²=a²+b²

c²=3136 +1089

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3 years ago

Laura sends an average of 27 text messages per month to each of f friends. Her cell phone provider charges her a flat rate of $3

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t(f) = 27*f

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2 years ago

Exhibit 15-2A regression model between sales (y in $1000s), unit price (x1 in dollars) and television advertisement (x2 in dolla

Semmy [17]

Answer:

Sales are expected to increase positively.

Step-by-step explanation:

The model is y =7-3*X1+5*X2

Here, y is the depended variable and X1 and X2 are independent variable.

Holding the unit price constant X2 (television advertisement) is increase by $1 dollar

SSR= 3500

SSE=1500

So, TSS = SSR+SSE = (3500+1500) = 5000

Now r^2= 1 - (SSR/TSS) = 1 - (3,500/5,000) = 1 - 0.70 = 0.30

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3 years ago

Determine the measure of each segment then indicate whether the statements are true or false

kupik [55]

Answer:

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

Step-by-step explanation:

Considering the graph

Given the vertices of the segment AB

A(-4, 4)

B(2, 5)

Finding the length of AB using the formula

$d_{AB}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(2-\left(-4\right)\right)^2+\left(5-4\right)^2}$

$=\sqrt{\left(2+4\right)^2+\left(5-4\right)^2}$

$=\sqrt{6^2+1}$

$=\sqrt{36+1}$

$=\sqrt{37}$

$d_{AB}\:=\sqrt{37}$

$d_{AB}=6.08$ units

Given the vertices of the segment JK

J(2, 2)

K(7, 2)

From the graph, it is clear that the length of JK = 5 units

so

$d_{JK}=5$ units

Given the vertices of the segment GH

G(-5, -2)

H(-2, -2)

Finding the length of GH using the formula

$d_{GH}\:=\:\sqrt{\left(x_2-x_1\right)^2+\left(y_2-y_1\right)^2}$

$=\sqrt{\left(-2-\left(-5\right)\right)^2+\left(-2-\left(-2\right)\right)^2}$

$=\sqrt{\left(5-2\right)^2+\left(2-2\right)^2}$

$=\sqrt{3^2+0}$

$=\sqrt{3^2}$

$\mathrm{Apply\:radical\:rule\:}\sqrt[n]{a^n}=a,\:\quad \mathrm{\:assuming\:}a\ge 0$

$d_{GH}\:=\:3$ units

Thus, from the calculations, it is clear that:

$d_{AB}=6.08$

$d_{JK}=5$

$d_{GH}\:=\:3$

Thus,

$d_{AB}\ne d_{JK}$

$d_{AB}\ne \:d_{GH}$

$d_{GH}\ne \:d_{JK}$

Therefore,

Option (A) is false

Option (B) is false

Option (C) is false

8 0

2 years ago