Answer: 1,071
Step-by-step explanation:
Lets analyze the equation:
<span>ax^2 - bx = 0
</span>x(ax - b) = <span>0
</span>Therefore if x = 0, the equation holds no <span>matter about a and b</span>:
0(0a - b) = 0
0 = 0
Answer:(a)x^2+2y^2=2
(b)In the attached diagram
Step-by-step explanation:Step 1: Multiply both equations by t
xt=t(cost -sint)\\ty\sqrt{2} =t(cost +sint)
Step 1: Multiply both equations by t
xt=t(cost -sint)\\ty\sqrt{2} =t(cost +sint)
Step 2:We square both equations
(xt)^2=t^2(cost -sint)^2\\(ty)^2(\sqrt{2})^2 =t^2(cost +sint)^2
Step 3: Adding the two equations
(xt)^2+(ty)^2(\sqrt{2})^2=t^2(cost -sint)^2+t^2(cost +sint)^2\\t^2(x^2+2y^2)=t^2((cost -sint)^2+(cost +sint)^2)\\x^2+2y^2=(cost -sint)^2+(cost +sint)^2\\(cost -sint)^2+(cost +sint)^2=2\\x^2+2y^2=2 hopes this helps
3/4 can be converted to eighths by multiplying by 2/2 to get 6/8. 7/8 - 6/8 = 1/8 So 1/8 of a cup is for the topping.
