Ask question

Ask question

All categories

3 years ago

15

Two polynomials P and D are given. Use either synthetic or long division to divide P(x) by D(x), and express P in the form P(x)

= D(x) · Q(x) + R(x). P(x) = 4x5 + 16x4 − 16x3 − x − 4, D(x) = x2 − 4

1 answer:

WINSTONCH [101]3 years ago

6 0

Attached is the solution, long division is hard to type out.
Hope it helps.

You might be interested in

What is (6 + 3e)4 - 5e and 3(x - 5) + 7(x + 2) ?

Dafna11 [192]

idk lol use photomath

6 0

3 years ago

Hanna is driving 480 miles. She has already driven 312 miles. What percent of her trip has she completed?

SVEN [57.7K]

Answer:

68%

Step-by-step explanation:

Hope this helps! :)

I would appreciate brainliest, if not that's ok!

5 0

3 years ago

Can someone help please

finlep [7]

Answer:

x=7 y=3

Step-by-step explanation:

-x+6y=11

2x-3y=5

-2x+12y=22

2x-3y=5

Add both equations

-2x+2x-3y+12=22+5

9y=27

y=3

plug y back in

-x+18=11

-x=-7

x=7

3 0

1 year ago

Which of the following steps were applied to abcd to obtain abcd

bulgar [2K]

Answer:

C.

Step-by-step explanation:

Move to the right 2 units,

Move down 2 units.

7 0

3 years ago

Read 2 more answers

The probability that a certain kind of component will survive a shock test is 3/4. Find the probability that exactly 2 of the ne

Marina86 [1]

Answer:

Therefore the required probability is $=\frac{27}{128}$

Step-by-step explanation:

The probability of success is $\frac{3}{4}$

The number of trial = 4

X= the items survive out of 4

$P(x=r)=^nC_rq^{n-r}p^r$ p =the probability of success and q = the probability failure.

p= $\frac{3}{4}$ and $q=(1-\frac{3}{4})=\frac{1}{4}$

$\therefore P(X=2)=^4C_2(\frac{1}{4} )^2(\frac{3}{4} )^2$

$=\frac{4!}{2!2!} (\frac{1}{16} )(\frac{9}{16} )$

$=\frac{27}{128}$

Therefore the required probability is $=\frac{27}{128}$

3 0

3 years ago