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3 years ago

15

Two polynomials P and D are given. Use either synthetic or long division to divide P(x) by D(x), and express P in the form P(x)

= D(x) · Q(x) + R(x). P(x) = 4x5 + 16x4 − 16x3 − x − 4, D(x) = x2 − 4

1 answer:

WINSTONCH [101]3 years ago

6 0

Attached is the solution, long division is hard to type out.
Hope it helps.

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The condition_______?proves that ∆ABC and ∆EFG are congruent by the SAS criterion.

snow_lady [41]

Answer:

(1) D.Angle C is congruent to to Angle F. (2) C. SSS. (3) C. cannot be congruent to.

Step-by-step explanation:

1)

From the given figure it is noticed that

$AC=EG$

$CB=GF$

According to SAS postulate, if two sides and the included angle of one triangle are congruent to two sides and the included angle of another triangle, then both triangles are congruent.

The included angles of congruent sides are angle C and angle G.

So, condition "Angle C is congruent to to Angle F" will prove that the ∆ABC and ∆EFG are congruent by the SAS criterion.

2)

If $AB\neq EF$

According to SSS postulate, if all three sides in one triangle are congruent to the corresponding sides in the other.

Since two corresponding sides are congruent but third sides of triangles are not congruent, therefore SSS criterion for congruence is violated.

3)

Since two corresponding sides are congruent but third sides of triangles are not congruent, therefore the included angle of congruent sides are different.

$\angle C\neq \angle G$

Therefore angle C and angle F cannot be congruent to each other.

4 0

3 years ago

Find the area of the largest square contained by a circle of radius r = 1cm. Explain your answer and justify that it is correct.

Elena-2011 [213]

Answer:

2 square cm

Step-by-step explanation:

Given :

A square is inscribed in a circle whose radius is r = 1 cm

Therefore, the diameter of the circle is 2 r = 2 x 1

= 2 cm.

So the diagonal of the square is 2r.

Using the Pythagoras theorem, we find each of the side of the triangle is $r \sqrt 2$ .

Therefore, the area of the square is given by $\text{(side)}^2$

= $(r\sqrt 2)^2$

$= 2 r^2$

$= 2 (1)^2$

$=2 \ cm^2$

Hence the area of the largest square that is contained by a circle of radius 1 cm is 2 cm square.

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3 years ago

Could I get some help here <br> I literally have the iq of a 2nd grader

ahrayia [7]

Answer:

x = 16

Step-by-step explanation:

Supplementary angles = 180

K + L = 180

137 + 3x - 5 = 180

132 + 3x = 180

3x = 180 - 132

3x = 48

x = 48/3

x = 16

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3 years ago

Which operation is performed in the derivation of the

yanalaym [24]

It’s =X+ and that’s ru answering

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3 years ago

60% of Herbert's movies are adventure movies. He has 18 adventure movies. How many movies does Herbert have in all?

Vera_Pavlovna [14]

Data:
x (Number of movies) = ?

$\frac{60}{100} *x = 18$
$0,6x = 18$
$x = \frac{18}{0,6}$
$\boxed{x = 30}$

Answer:
<span>Herbert have in all ?
30 movies</span>

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3 years ago