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3 years ago

Please help. I will give 15 points.

Mathematics

2 answers:

Aneli [31]3 years ago

8 0

Answer:

its A

Step-by-step explanation:

vlabodo [156]3 years ago

4 0

Answer:

A, bc 7 divided by 1/5 is 35 so it makes the most sense other than 1/35

Step-by-step explanation:

Hoped I helped Im Eve btw. Have an amazing day and consider marking this as brainliest if you do thank you in advanced! :3

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Many televisions are classified by the length of the diagonal of their screens. A 60 in. television has a screen height of 32 in

Colt1911 [192]

The 60 inch is diagonal of or the hypotenuse of the TV so we are going to use a^2+b^2=c^2 and let width to be a, then we solve the problem.
a^2=c^2-b^2
oh, take the square root of both sides.
a=((c^2-b^2))^(1/2)
plug 60 for c, 32 for b, and the Width is equal to 50.75 for significant figures.

7 0

3 years ago

Solving separable differential equation DY over DX equals xy+3x-y-3/xy-2x+4y-8

Ivanshal [37]

It looks like the differential equation is

$\dfrac{dy}{dx} = \dfrac{xy + 3x - y - 3}{xy - 2x + 4y - 8}$

Factorize the right side by grouping.

$xy + 3x - y - 3 = x (y + 3) - (y + 3) = (x - 1) (y + 3)$

$xy - 2x + 4y - 8 = x (y - 2) + 4 (y - 2) = (x + 4) (y - 2)$

Now we can separate variables as

$\dfrac{dy}{dx} = \dfrac{(x-1)(y+3)}{(x+4)(y-2)} \implies \dfrac{y-2}{y+3} \, dy = \dfrac{x-1}{x+4} \, dx$

Integrate both sides.

$\displaystyle \int \frac{y-2}{y+3} \, dy = \int \frac{x-1}{x+4} \, dx$

$\displaystyle \int \left(1 - \frac5{y+3}\right) \, dy = \int \left(1 - \frac5{x + 4}\right) \, dx$

$\implies \boxed{y - 5 \ln|y + 3| = x - 5 \ln|x + 4| + C}$

You could go on to solve for $y$ explicitly as a function of $x$ , but that involves a special function called the "product logarithm" or "Lambert W" function, which is probably beyond your scope.

8 0

1 year ago

Use the table below to complete exercise 7

12345 [234]

C is the answer I believe

3 0

2 years ago

Engineers must consider the diameters of heads when designing helmets. The company researchers have determined that the populati

Margaret [11]

Answer:

1. The minimum head breadth that will fit the clientele is of 4.41-in.

2. The maximum head breadth that will fit the clientele is of 7.19-in.

Step-by-step explanation:

Normal Probability Distribution:

Problems of normal distributions can be solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Normally distributed with a mean of 5.8-in and a standard deviation of 0.8-in.

This means that $\mu = 5.8, \sigma = 0.8$

1. What is the minimum head breadth that will fit the clientele?

The 4.1st percentile, that is, X when Z has a pvalue of 0.041, so X when Z = -1.74.

$Z = \frac{X - \mu}{\sigma}$

$-1.74 = \frac{X - 5.8}{0.8}$

$X - 5.8 = -1.74*0.8$

$X = 4.41$

The minimum head breadth that will fit the clientele is of 4.41-in.

2. What is the maximum head breadth that will fit the clientele?

100 - 4.1 = 95.9th percentile, that is, X when Z has a pvalue of 0.959, so X when Z = 1.74.

$Z = \frac{X - \mu}{\sigma}$

$1.74 = \frac{X - 5.8}{0.8}$

$X - 5.8 = 1.74*0.8$

$X = 7.19$

The maximum head breadth that will fit the clientele is of 7.19-in.

8 0

2 years ago

I don't really understand this, please help. Also, if you could show how you got your answer, that would help.

Varvara68 [4.7K]

What is 20% of 100? It would be 20! so 120
120-30%=84.
a. 84 pumpkins were left.
b. The final number of pumpkins were less than Brianna had hoped for.

hope this helps! :)

3 0

3 years ago