Answer:
the three numbers = -8, -32, -30
Step-by-step explanation:
let the first number = a
let the second number = b
let the third number = c
From the first statement: b = 4a
From the second statement: c = b + 2
From the third statement: b - 2c = 28
From the above equations, we can solve (1) and (2) together.
c = b + 2
b = c - 2
Also, b - 2c = 28
(c - 2) - 2c = 28
c - 2 - 2c = 28
-c = 30
c = -30
b = -30 - 2
= -32
b = 4a
a = b/4
a = -32/4
a = -8
Therefore, the three numbers = -8, -32, -30
There are no reasonable conclusions on your list of statements,
because, as far as we know, you have no list. The only things
we know that you have are a leaky faucet and an empty bucket.
![\bf \textit{volume of a cylinder}\\\\ V=\pi r^2 h~~ \begin{cases} r=radius\\ h=height\\[-0.5em] \hrulefill\\ r=6\\ h=15 \end{cases}\implies \begin{array}{llll} V=\pi (6)^2(15)\implies V=540\pi \\\\\\ V\approx 1696.46 \end{array}](https://tex.z-dn.net/?f=%5Cbf%20%5Ctextit%7Bvolume%20of%20a%20cylinder%7D%5C%5C%5C%5C%20V%3D%5Cpi%20r%5E2%20h~~%20%5Cbegin%7Bcases%7D%20r%3Dradius%5C%5C%20h%3Dheight%5C%5C%5B-0.5em%5D%20%5Chrulefill%5C%5C%20r%3D6%5C%5C%20h%3D15%20%5Cend%7Bcases%7D%5Cimplies%20%5Cbegin%7Barray%7D%7Bllll%7D%20V%3D%5Cpi%20%286%29%5E2%2815%29%5Cimplies%20V%3D540%5Cpi%20%5C%5C%5C%5C%5C%5C%20V%5Capprox%201696.46%20%5Cend%7Barray%7D)
notice, the cup can take that much in cm³, so it can surely take 1620 just fine.
The graph looks accurate make sure you create a table of values and clearly dot the points at (0,-3) and (2,-3).