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3 years ago

How do you know am equation has no solution?

2 answers:

Natasha2012 [34]3 years ago

7 0

If u work it out and both sides don't equal, then there is no solution.
Example :
2x + 4 = 2x + 6
2x - 2x = 6 - 4
0 = 2....this is incorrect...therefore, there is no solution

Elden [556K]3 years ago

4 0

A quadratic equation can have no real solution
a $a x^{2} +bx+c=0$
If $b^{2} -4ac\ \textless \ 0$ then the equation has no real solutions
Even simultaneous equations can have no solutions
$ax+by=c------1$
$ax+by=d------2$
I these two equations the two expressions equal different things, so the equation has no solutions

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Answer:

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Step-by-step explanation:

The equation is equal to -24 = -19. That's not true

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3 years ago

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URGENT WILL GIVE YOU 100 POINTS PLEASE ANSWER CORRECTLY

wariber [46]

Answer:

1. x = 18.4

2. x = -1.25

3. x = $\frac{5}{12}$

4. x = 12.3

5. x = 6.4

6. z = 5.8

7. x = $\frac{1}{12}$

8. x = - $\frac{1}{4}$

9. x = $\frac{1}{3}$

10. x = -9

11. z = 18

12. x = 7

13. x = -9

14. x = -36

15. x = -7

16. x = 8

17. z = -1.5

18. x = - $\frac{45}{7}$

19. x = 16

20. x = -12

21. x = $\frac{8}{3}$

22. x = -1.6

23. x = 1.8

24. x = -8.2

Step-by-step explanation:

1. x - 3.5 = 14.9 (add 3.5 to each side)

x = 18.4

2. x + 2.25 = 1 (subtract 2.25 from each side)

x = -1.25

3. - $\frac{1}{3}$ = x - $\frac{3}{4}$ (add $\frac{3}{4}$ to each side)

$\frac{3}{4}$ - $\frac{1}{3}$ = x (multiply $\frac{3}{4}$ by $\frac{3}{3}$ and $\frac{1}{3}$ by $\frac{4}{4}$ to get a common denominator)

$\frac{9}{12}$ - $\frac{4}{12}$ = x

$\frac{5}{12}$ = x

4. x - 2.8 = 9.5 (add 2.8 to each side)

x = 12.3

5. x - 8.5 = -2.1 (add 8.5 to each side)

x = 6.4

6. z - 9.4 = -3.6 (add 9.4 to each side)

z = 5.8

7. x + $\frac{5}{6}$ = $\frac{11}{12}$ (subtract $\frac{5}{6}$ from each side)

x = $\frac{11}{12}$ - $\frac{5}{6}$ (multiply $\frac{5}{6}$ by $\frac{2}{2}$ to get a common denominator)

x = $\frac{11}{12}$ - $\frac{10}{12}$

x = $\frac{1}{12}$

8. - $\frac{5}{6}$ + x = - $\frac{13}{12}$ (add $\frac{5}{6}$ to each side)

x = $\frac{5}{6}$ - $\frac{13}{12}$ (multiply $\frac{5}{6}$ by $\frac{2}{2}$ to get a common denominator)

x = $\frac{10}{12}$ - $\frac{13}{12}$

x = - $\frac{3}{12}$ = - $\frac{1}{4}$

9. x - $\frac{1}{9}$ = $\frac{5}{18}$ (add $\frac{1}{9}$ to each side)

x = $\frac{1}{9}$ + $\frac{5}{18}$ (multiply $\frac{1}{9}$ by $\frac{2}{2}$ to get a common denominator)

x = $\frac{2}{18}$ + $\frac{5}{18}$

x = $\frac{6}{18}$ = $\frac{3}{9}$ = $\frac{1}{3}$

10. x + 6 = -3 (subtract 6 from each side)

x = -9

11. z - 7 = 11 (add 7 to each side)

z = 18

12. -1 = x - 8 (add 8 to each side)

7 = x

13. -4x = 36 (divide each side by -4)

x = -9

14. - $\frac{x}{3}$ = 12 (multiply each side by -3)

x = -36

15. 63 = -9x (divide each side by -9)

-7 = x

16. 6.4 = 0.8x (divide each side by 0.8)

8 = x

17. -2.8z = 4.2 (divide each side by -2.8)

z = -1.5

18. - $\frac{7}{9}$ x = 5 (divide each side by - $\frac{7}{9}$ )

x = $\frac{5}{1}$ ÷ - $\frac{7}{9}$

x = $\frac{5}{1}$ (times) - $\frac{9}{7}$

x = - $\frac{45}{7}$

19. $\frac{1}{2}$ x = 8 (divide each side by $\frac{1}{2}$ )

x = 16

20. - $\frac{3}{4}$ x = 9 (divide each side by - $\frac{3}{4}$ )

x = -12

21. - $\frac{7}{8}$ x = - $\frac{21}{64}$ (divide each side by - $\frac{7}{8}$ )

x = - $\frac{7}{8}$ ÷ - $\frac{21}{64}$

x = - $\frac{7}{8}$ (times) - $\frac{64}{21}$

x = $\frac{448}{168}$ = $\frac{56}{21}$ = $\frac{8}{3}$

22. 1.6x = -3.2 (divide each side by 1.6)

x = -1.6

23. - $\frac{1}{2}$ = - $\frac{5}{18}$ x (divide each side by - $\frac{5}{18}$ )

1.8 = x

24. -2.5x = 20.5 (divide each side by -2.5)

x = -8.2

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2 years ago

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Andrej [43]

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4 years ago

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