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RUDIKE [14]
2 years ago
10

Pls need help to Divide 40x/64y by 5x/8y

Mathematics
2 answers:
Stolb23 [73]2 years ago
4 0
<h3>Answer:</h3>

1

<h3>Step-by-step explanation:</h3>

The first fraction reduces to 5x/(8y), identical to the second fraction. When something is divided by itself, the result is 1.

allsm [11]2 years ago
4 0

40x/64y / 5x/8y
K C F
40x/64y * 8y/5x

320xy / 320xy

1 <---------- answer
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Um comerciante comprou um lote de cabos e quer colocá-los à venda em pedaços, o maior possível, com o mesmo comprimento e sem ha
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Answer:

12

Step-by-step explanation:

The computation of the size of the customers is shown below:

Here we find the greatest common divisor of the given numbers

96, 60, 84 ÷ 2

48, 30, 42  ÷ 2

24, 15, 21 ÷ 2

12, 15, 21 ÷ 2

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3, 15, 21  ÷ 3

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1, 1, 7 ÷ 7

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By this there are three numbers i.e. 2, 2 and 3

So, the lease common denominator is

= 2 × 2 × 3

= 12

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2 years ago
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Answer:

sqrt(11)

Step-by-step explanation:

3^3+sqrt2^2=11

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3 years ago
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A bag contains coins of rupees 2 Rupees 1 and 50 paise, in ratio of 1 is to 2 is to 4. if the total amount is rupees 72 find how
BabaBlast [244]

Answer:

<u>Final </u><u>answer </u><u>-</u>

number \: of \: 50 \: paise \: coins \: in \: the \: bag = 4x \\ \dashrightarrow{4 \times 12 = 48 \: coins}

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4 0
2 years ago
Find the length of a line segment with endpoints of –9 and 7.
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Step-by-step explanation:

7 0
3 years ago
Katya made another set of dolls. In the new set, the largest doll has a diameter of 8.75 cm and a height of 15.6 cm. Is this a d
Natali5045456 [20]

<em>Complete Question:</em>

<em>Katya creates handmade sets of dolls, which is sold to craft and souvenir stores. The first set of dolls has a middle diameter of 7cm and a height of 12cm.</em>

<em>Katya made another set of dolls. In the new set, the largest doll has a diameter of 8.75 cm and a height of 15.6 cm. Is this a dilation of the first set of dolls? </em>

<em></em>

Answer:

The new set is not a dilation of the first set

Step-by-step explanation:

Given

First Set:

Height = 12cm

Diameter = 7cm

New Set:

Height = 15.6cm

Diameter = 8.75cm

Required

Determine if the new set is a dilation of the second

To do this, we pass through the following steps:

1. Divide the height of the first set by the new set

2. Divide the diameter of the first set by the new set

3. Result in (1) and (2) must be equal if the new set is a dilation of the first set

Following the steps above:

(1)

Height\ Ratio = \frac{H_2}{H_1}

Height\ Ratio = \frac{15.6}{12}

Height\ Ratio = 1.3

(2)

Diameter\ Ratio = \frac{D_2}{D_1}

Diameter\ Ratio = \frac{8.75}{7}

Diameter\ Ratio = 1.25

(3) Make comparison

The ratio in (1) does not equal the ratio in (2)

i.e.

1.3 \neq 1.25

<em>Hence, the new set is not a dilation of the first set</em>

7 0
3 years ago
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