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2 years ago

PLEASE HELP ME ASAP!!!! ILL MARK BRIANLIEST AND GIVE EXTRA POINTS

Mathematics

2 answers:

vivado [14]2 years ago

7 0

Answer:

4. 7/9 (b - 27) > 49/81

=> 7/9b - 21 > 49/81

=> 7/9b - 21 > 7/9

=> 7/9b -21 + 21 > 7/9 + 21

=> 7/9b > 7/9 + 189/9

=> 7/9b > 196/9

=> 7/9b / 7/9 > 196/9 / 7/9

=> To divide fractions, take the reciprocal of the divisor fraction and then multiply.

=> b > 196/9 x 9/7

=> b > 1764 / 63

=> b > 28

4th answer is b > 28

5. This question doesn't make any sense.

=> 11w - 8w greater or equal to 14w

=> 3w greater or equal to 14w.

If we make "w" as any number, this equation will not come true as 14 is larger than 3.

This answer may be correct the equation is like:

3w is smaller or equal to 14w.

kumpel [21]2 years ago

3 0

Answer:

b > 250/9 and w ≥ 0

Step-by-step explanation:

7/9 (b - 27) > 49/81

First, simplify both sides of the inequality:

7/9b - 21 > 49/81

Add 21 to both sides

7/9b - 21 +21 > 49/81 +21

Multiply both sides by 9/7

9/7 x 7/9b > 49/81 x 9/7

b > 1750/81

Simplify

b > 250/9

11w - 8w ≥ 14w

Simplify both sides once again

3w ≥ 14w

Subtract 14w from both sides

3w - 14w ≥ 14w - 14w

-11w ≥ 0

Divide both sides by -11w

w ≥ 0

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Read 2 more answers

Ben consumes an energy drink that contains caffeine. After consuming the energy drink, the amount of caffeine in Ben's body decr

Airida [17]

Answer:

The 5-hour decay factor for the number of mg of caffeine in Ben's body is of 0.1469.

Step-by-step explanation:

After consuming the energy drink, the amount of caffeine in Ben's body decreases exponentially.

This means that the amount of caffeine after t hours is given by:

$A(t) = A(0)e^{-kt}$

In which A(0) is the initial amount and k is the decay rate, as a decimal.

The 10-hour decay factor for the number of mg of caffeine in Ben's body is 0.2722.

1 - 0.2722 = 0.7278, thus, $A(10) = 0.7278A(0)$ . We use this to find k.

$A(t) = A(0)e^{-kt}$

$0.7278A(0) = A(0)e^{-10k}$

$e^{-10k} = 0.7278$

$\ln{e^{-10k}} = \ln{0.7278}$

$-10k = \ln{0.7278}$

$k = -\frac{\ln{0.7278}}{10}$

$k = 0.03177289938
$

Then

$A(t) = A(0)e^{-0.03177289938t}$

What is the 5-hour growth/decay factor for the number of mg of caffeine in Ben's body?

We have to find find A(5), as a function of A(0). So

$A(5) = A(0)e^{-0.03177289938*5}$

$A(5) = 0.8531$

The decay factor is:

1 - 0.8531 = 0.1469

The 5-hour decay factor for the number of mg of caffeine in Ben's body is of 0.1469.

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3 years ago

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suter [353]

Answer:

Step-by-step explanation:

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3 years ago

For a class trip, 114 students are put on buses. At this rate, how many students would be on eight buses? Show your work.

vredina [299]

Answer:

Not really sure but 14.25 students seem to be the correct answer.

Step-by-step explanation:

114:8 = 14.25

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10 months ago