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Marrrta [24]
4 years ago
8

Complete these exercises to review the things you need this module

Mathematics
2 answers:
Arada [10]4 years ago
7 0
5. 6 times 3= 18in squared 
6. 7.6 times 7.6= 57.76m squared
7. 3.25 times 2.5= <span>8.125ft squared
8. 8.2 times 5.1=41.82</span>
NARA [144]4 years ago
5 0
5. 18
6. 57.76
7. 8 1/8
8. 20.91
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The area of a rectangle is 5.472 m2. If the length of the rectangle is 0.72 m, what is the width of the rectangle?​
LUCKY_DIMON [66]

Answer:0.89

Step-by-step explanation:

3 0
3 years ago
Given the system of equations, what is the solution?<br><br> 3x - 2y + 10 = 0<br> 5y = 4x + 8
Nina [5.8K]
Top equation, minus 10 both sides to get
3x-2y=-10

bottom equation, minus 4x both sides
5y-4x=8
-4x+5y=8

now elimiate y's


multiply top equation by 5 and bottom equaiton by 2 and add them together

15x-10y=-50
<u>-8x+10y=16 +</u>
7x+0y=-34

7x=-34
divide both sides by 7
x=-34/7

sub back

3x-2y=-10
3(-34/7)-2y=-10
(-102/7)-2y=-10
add (102/7) to both sides
-2y=-10+(102/7)
-2y=(-70/7)+(102/7)
-2y=32/7
divide both sides by -2, or times both sides by -1/2
y=-32/14
y=-16/7


(x,y)
(-34/7,-16/7)
6 0
4 years ago
Read 2 more answers
what is the slope of a line perpendicular to the line whose equations is 2x-12y=168. fully reduce your answer
Blizzard [7]

Answer:

-6

Step-by-step explanation:

The equation 2x-12y=168 is in standard form so in order to dtermine the slope you need to convert it to slope-intercept form.

1. subtract 2x from both sides.

-12y=-2x+168

2. divide all terms by -12 (to isolate the y)

y=1/6x-14

3. the equation of a line that is the perpendicular is the opposite and reciprocal of the given slope.

the opposite of 1/6 is -1/6.

The reciprocal of -1/6 is -6/1 OR -6.

-6 is the slope of a line pependicular to 2x-12y=168.

Hope this helps.

4 0
4 years ago
How do you calculate this? Help
Ipatiy [6.2K]
3.5 I think ... I’ll
6 0
3 years ago
PLEASE HELP QUICK. I'M OFFERING 10PTS (More than it's worth) AND BRAINLIEST ANSWSER
neonofarm [45]
In the picture you can find the simplied forms of the equations.

7 0
3 years ago
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