Complete these exercises to review the things you need this module

Mathematics

2 answers:

Arada [10]3 years ago

7 0

5. 6 times 3= 18in squared
6. 7.6 times 7.6= 57.76m squared
7. 3.25 times 2.5= <span>8.125ft squared
8. 8.2 times 5.1=41.82</span>

NARA [144]3 years ago

5 0

5. 18
6. 57.76
7. 8 1/8
8. 20.91

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Help me with these problems please

Scorpion4ik [409]

1. y = 7
2. 0
3. m = -1
4. k = -4
5. x = -6
6. There is no solution for these equations.

Please let me know if you want explanations/work shown!! Hope this helps :)

7 0

4 years ago

Please Help! Thanks to whoever can answer this!

Illusion [34]

Here, we are missing the slope and the y intercept.

Lets look for the y intercept first.

Where does it cross the y axis? At 3!!

3 is the y intercept.

Now, find the slope by using the slope formula.

$m = \frac{y2 - y1}{x2 - x1}$
(0,3) and (2,1)

m = 1-3/2-0 = -2/2 = -2/2 = -1
m = -1

Okay, so we found our slope, now just write the equation.

Answer: y = -1x + 3

8 0

3 years ago

16) Please help with question. WILL MARK BRAINLIEST + 10 POINTS.

Katyanochek1 [597]

We will use the sine and cosine of the sum of two angles, the sine and consine of $\frac{\pi}{2}$ , and the relation of the tangent with the sine and cosine:

$\sin (\alpha+\beta)=\sin \alpha\cdot\cos\beta + \cos\alpha\cdot\sin\beta

\cos(\alpha+\beta)=\cos\alpha\cdot\cos\beta-\sin\alpha\cdot\sin\beta$

$\sin\dfrac{\pi}{2}=1,\ \cos\dfrac{\pi}{2}=0$

$\tan\alpha = \dfrac{\sin\alpha}{\cos\alpha}$

If you use those identities, for $\alpha=x,\ \beta=\dfrac{\pi}{2}$ , you get:

$\sin\left(x+\dfrac{\pi}{2}\right) = \sin x\cdot\cos\dfrac{\pi}{2} + \cos x\cdot\sin\dfrac{\pi}{2} = \sin x\cdot0 + \cos x \cdot 1 = \cos x$

$\cos\left(x+\dfrac{\pi}{2}\right) = \cos x \cdot \cos\dfrac{\pi}{2} - \sin x\cdot\sin\dfrac{\pi}{2} = \cos x \cdot 0 - \sin x \cdot 1 = -\sin x$

Hence:

$\tan \left(x+\dfrac{\pi}{2}\right) = \dfrac{\sin\left(x+\dfrac{\pi}{2}\right)}{\cos\left(x+\dfrac{\pi}{2}\right)} = \dfrac{\cos x}{-\sin x} = -\cot x$