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Molodets [167]
3 years ago
6

Hey bro's help me!!​

Mathematics
2 answers:
White raven [17]3 years ago
8 0

Answer:

-7 and 12 gl

Step-by-step explanation:

sweet [91]3 years ago
3 0

Answer:

1. -7

2. 12

Step-by-step explanation:

Hope this helps :)

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Does second-hand smoke increase the risk of a low birthweight? A baby is considered have low birthweight if he/she weighs less t
marishachu [46]

Answer:

Option 2) Null hypothesis: p = 0.078 , Alternate hypothesis: p > 0.078

Step-by-step explanation:

We are given the following in the question:

According to the National Center of Health Statistics, about 7.8% of all babies born in the U.S. are categorized as low birth weight.

Sample size, n = 1200

p = 7.8% = 0.078

We have to carry a hypothesis test whether national percentage is higher than 7.8% or not.

Thus, we can design the null and the alternate hypothesis

H_{0}: p = 0.078\H_A: p > 0.078

Thus, the correct answer is:

Option 2) Null hypothesis: p = 0.078 , Alternate hypothesis: p > 0.078

5 0
2 years ago
What is m∠A?<br> Help please this is overdue
Talja [164]
Can you show the multiple choice one
6 0
2 years ago
A box of chocolates contains 18 chocolate squares, tens of the square are milk chocolate, 5 are dark chocolate, and 3 are.white
Step2247 [10]

Answer:

0.167 ; 0.093

Step-by-step explanation:

Given that:

Total number of chocolate squares = 18 of which÷

Number of milk chocolate square = 10

Dark chocolate square = 5

White chocolate square= 3

Probability of choosing a white chocolate square :

Probability = required outcome / Total possible outcomes

Required outcome = white chocolate square = 3

Number of chocolate square = 18

P(choosing a white chocolate square) = 3 / 18 = 1/6 =

B) probability of randomly selecting a milk chocolate first, replace it, and then select a white chocolate?

With replacement :

First pick :

Number milk chocolate = 10

P(choosing a milk chocolate) = 10/18 = 5/9

Second pick:

Number of white chocolate = 3

P(choosing a white chocolate) = 3 / 18 = 1/6

Hence, since both probabilities are independent :

P(choosing milk, then white chocolate) :

(5/9 × 1/6) = 5/54 = 0.0925 = 0.093

8 0
3 years ago
Suppose there are three types of consumers who attend concerts at your university’s performing arts center: students, staff, and
Alchen [17]

Answer: i. There are 140 students willing to pay $20.

ii. There are 200 staff members willing to pay $35.

iii. There are 100 faculty members willing to pay $50.

Step-by-step explanation: Suppose there are three types of consumers who attend concerts at Marshall university's performing arts center: students, staff, and faculty. Each of these groups has a different willingness to pay for tickets; within each group, willingness to pay is identical. There is a fixed cost of $1,000 to put on a concert, but there are essentially no variable costs.

For each concert:

A) If the performing arts center can charge only one price, what price should it charge? What are profits at this price? B) If the performing arts center can price discriminate and charge two prices, one for students and another for faculty/staff, what are its profits?

C) If the performing arts center can perfectly price discriminate and charge students, staff, and faculty three separate prices, what are its profits?

8 0
2 years ago
How do I solve this problem using the substitution method <br> x-3y=4<br> 4x-2y=26
Nastasia [14]
Top 1. Substitute 3y on both sides of the equation.
Bottom 2. Substitute 2y on both sides of the equation

3y and 2y cancel

Divide x by 4 and 26 by 4.

Is there die points on a graph or decimal?

I have not done this for years but there is many calculators that can show you step by step online. I recommend using these
5 0
2 years ago
Read 2 more answers
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