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ANEK [815]
3 years ago
13

The side lengths of triangle ABC are 3, 4, and 5. Which set of ordered pairs form a triangle that is congruent to triangle ABC?

Mathematics
1 answer:
Ludmilka [50]3 years ago
6 0
FORMULA:
AREA=     AC x h
        ----------------------
                    2
PERIMETER= AB+BC+CA

AREA   =   SQUAREROOT       
                  S(S-AB)(S-BC)(A-CA)


S= AB+BC+CA=   P
     -----------------   -----
               2             2


FOR THE COMPLETE SOLUTION PLEASE SEE THE PICTURE. THANKS.

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Solve for m<br><img src="https://tex.z-dn.net/?f=g%20%3D%204cm%20-%203m" id="TexFormula1" title="g = 4cm - 3m" alt="g = 4cm - 3m
ozzi
This is what is called a literal equation.  Solve it for m just like you would solve any equation for x.  Isolate the term with the variable you're looking for.  Do this by subtracting 4cm from both sides to give you g - 4cm = -3m.  Now we need to divide by -3 to get m alone: \frac{g-4cm}{-3}=m.  Or we could lose the negative on the 3 in the denominator like this: \frac{-g+4cm}{3}=m and \frac{4cm-g}{3}=m.  There you go!  Any one of those last three would work.  It just depends upon how your teacher wants you to express your answer.
7 0
3 years ago
An electrician needs 3/5 of a roll of electrical wire to wire each room in a house. How many rooms can he wire with 3 3/5 rolls
Airida [17]
6
The electrician can wire 6 rooms with 3 3/5 rolls of wire;
3 3/5= 18/5
18/5 divided by 3/5= 6
8 0
3 years ago
Consider two functions f and g on [1, 8] such that integral^8_1 f(x) dx = 9, integral^8_1 g(x) dx = 5, integral^8_5 f(x) dx = 4,
Gelneren [198K]

I'll abbreviate the definite integral with the notation,

I(f(x),a,b)=\int_a^bf(x)\,\mathrm dx

We're given

  • I(f,1,8)=9
  • I(g,1,8)=5
  • I(f,5,8)=4
  • I(g,1,5)=3

Recall that the definite integral is additive on the interval [a,b], meaning for some c\in[a,b] we have

I(f,a,b)=I(f,a,c)+I(f,c,b)

The definite integral is also linear in the sense that

I(kf+\ell g,a,b)=kIf(a,b)+\ell I(g,a,b)

for some constant scalars k,\ell.

Also, if a\ge b, then

I(f,a,b)=-I(f,b,a)

a. I(2f,1,5)=2I(f,1,5)=2(I(f,1,8)-I(f,5,8))=2(9-4)=\boxed{10}

b. I(f-g,1,8)=I(f,1,8)-I(g,1,8)=9-5=\boxed{4}

c. I(f-g,1,5)=I(f,1,5)-I(g,1,5)=\dfrac{I(2f,1,5)}2-I(g,1,5)=10-3=\boxed{7}

d. I(g-f,5,8)=I(g,5,8)-I(f,5,8)=(I(g,1,8)-I(g,1,5))-I(f,5,8)=(5-3)-4=\boxed{-2}

e. I(7g,5,8)=7I(g,5,8)=7(5-3)=\boxed{14}

f. I(3f,5,1)=3I(f,5,1)=-3I(f,1,5)=-\dfrac32I(2f,1,5)=-\dfrac32(10)=\boxed{-15}

4 0
3 years ago
If you were to place $5,000 in a savings account that pays 6% interest compounded continuously, how much money will you have aft
ANTONII [103]

Answer: D

Step-by-step explanation: Use money chip calculator

5 0
3 years ago
What is the percent of 840 is 546
lesantik [10]
K so its an equation      546         x
                                   over   = over
                                   840       100
when u do cross multiplication it will be 840x=546 * 100
                                                       x is about 64%
Hope this is helpful
4 0
3 years ago
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