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aniked [119]
3 years ago
12

How many options are there for picking 5 students out of 30 to wash my car

Mathematics
1 answer:
kirza4 [7]3 years ago
3 0

Answer:

120

Step-by-step explanation:

5 factorial

5 x 4 x 3 x 2 x 1 = 120

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The solids are similar. Find the volume V of the larger solid.
diamong [38]

Answer:

9604

Step-by-step explanation:

V = (7/3)³ × 756

= 343/27 × 756

= 9604 ft³

4 0
3 years ago
Mr. Adams has 14 boys and 8 girls in his mathematics class. If he chooses
scZoUnD [109]

Answer:

it is more likely that both of the students will be boys because there are 14 boys and 8 girls. 14 is greater than 8. So, both of the students that are chosen will be boys,

5 0
3 years ago
The ratio to hearts to moons is | The ratio of moons to all shapes is. I need help due in 10 minutes
Alinara [238K]

Hearts to moon= 6:4

                         = 3:2 (simplified)

Moon to all shapes= 4:10

                               = 2:5 (simplified)

4 0
3 years ago
Read 2 more answers
Find the common ratio of the geometric sequence -18,126,-882
gtnhenbr [62]

Answer:

r = - 7

Step-by-step explanation:

The common ratio r is the ratio of a term to the preceding term, that is

r = 126 ÷ - 18 = - 882 ÷ 126 = - 7

5 0
3 years ago
Find a general term an for the sequence whose first four terms are given.<br> 2, 4, 8, 16, ...
lapo4ka [179]

Answer:

  an = 2·2^(n-1)

Step-by-step explanation:

There are simple tests to determine whether a sequence is arithmetic or geometric. The test for an arithmetic sequence is to check to see if the differences between terms are the same. Here the differences are 2, 4, 8, so are not the same.

The test for a geometric sequence is to check to see if the ratios of terms are the same. Here, the ratios are ...

  4/2 = 2

  8/4 = 2

  16/8 = 2

These ratios are all the same (they are "common"), so the sequence is geometric.

The general term of a geometric sequence with first term a1 and common ratio r is ...

  an = a1·r^(n-1)

Filling in the values for this sequence, we find the general term to be ...

  an = 2·2^(n-1)

7 0
3 years ago
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