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zalisa [80]
3 years ago
6

The curved part of this figures is a semicircle.

Mathematics
2 answers:
ddd [48]3 years ago
5 0
The answer is 14 + 8.125 units. 
vovangra [49]3 years ago
3 0

First we join the two endpoints of the semicircle and that will be the diameter.

And to find the length of the diameter, we have to use distance formula, with one endpoint (3,2) and the other is (-4,-2) .

SO we get

Diameter = \sqrt{ {-4-3)^2 +(-2-2)^2 } = \sqrt{49+16} = \sqrt 65

Radius is half of diameter, so the radius is

Radius= \frac{ \sqrt{65}}{2}

Formula of area of circle is

Area = \pi r^2

So the area of semicircle is

=(1/2) \pi ( \frac{ \sqrt{65}}{2})^2 = 8.125 \pi \square \units

And the other figure is a triangle, with

Base = 3-(-4)=3+4=7 \\ height = 2-(-2) = 2+2 =4

Area = (1/2)*4*7= 14 square units

Therefore, total area is the sum of area of semicircle and area of triangle,

And we will get

Total \ area= 14 + 8.125 \pi \ units^2

Correct option is the third option .

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Answer:

cos\ V = \frac{2\sqrt{29}}{29}

Step-by-step explanation:

Given

The attached triangle

Required

Find cos V

In trigonometry:

cos\theta = \frac{Adjacent}{Hypotenuse}

In this case:

cos V= \frac{TV}{UV}

Where

TV = 6

and

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UV^2 = 6^2 + 15^2

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UV = \sqrt{9*29

UV = \sqrt{9} *\sqrt{29

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cos V= \frac{TV}{UV}

cos\ V = \frac{6}{3\sqrt{29}}

cos\ V = \frac{2}{\sqrt{29}}

Rationalize:

cos\ V = \frac{2}{\sqrt{29}}*\frac{\sqrt{29}}{\sqrt{29}}

cos\ V = \frac{2\sqrt{29}}{29}

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