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vova2212 [387]
3 years ago
7

What is the center and radius of the circle with equation x2 + y2 + 6x + 16y + 64 = 0?

Mathematics
1 answer:
almond37 [142]3 years ago
5 0
Hello,
 
By making factors:
x^2+y^+2+6x+16y+64=0\\
x^2+6x+9+y^2+16y+64-9=0\\
(x+3)^2+(y+8)^2=9\\
radius=3




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Step-by-step explanation:

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We will define a variable ( x ) as the time it took for Jo Anne to give her speech at home.

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Jo Anne gave her speech which was 10 seconds less than the one she practised at home. We will convert the time in seconds to minutes as follows:

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The time taken by Jo Anne to complete her speech in English class can be represented as:

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Using the range of time that Jo Anne could take in delivering her speech in the class would be:

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                            0 - 1/6 < y < 4 - 1/6

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Since time can not be less than zero. We correct the lower limit to " 0 " as follows:

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