3 years ago

What is the center and radius of the circle with equation x2 + y2 + 6x + 16y + 64 = 0?

1 answer:

5 0

Hello,

By making factors:
$x^2+y^+2+6x+16y+64=0\\
x^2+6x+9+y^2+16y+64-9=0\\
(x+3)^2+(y+8)^2=9\\
radius=3

$

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