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Serga [27]
4 years ago
10

A company implements the stateless DHCPv6 method for configuring IPv6 addresses on employee workstations. After a workstation re

ceives messages from multiple DHCPv6 servers to indicate their availability for DHCPv6 service, which message does it send to a server for configuration information?
Computers and Technology
2 answers:
julsineya [31]4 years ago
6 0

Answer:

DHCPv6 INFORMATION-REQUEST is the correct answer

Explanation:

frez [133]4 years ago
4 0

Answer:

DHCPV6 INFORMATION-REQUEST.

Explanation:

The DHCP protocol is a service protocol that provides IP address and other communication information for client workstations from the server.

The DHCPV6 INFORMATION-REQUEST is used by a client to request for ipv6 address and additional information. The router solicit message is sent by a client to seek for available DHCPV6 servers. The DHCPV6 server sends a router advertisement message to the client, to confirm its availability.

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7 0
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Write a routine to interchange the mth and nth elements of a singly-linked list. You may assume that the ranks m and n are passe
IRINA_888 [86]

Answer:

//The routine to swap m th and nth ranked elements

void swapmAndn(int m, int n)

{

  //Set the linked list head node

  Linked_Node **node_head

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  //set previous node  

  Linked_Node *node_prev = NULL;

 

  //set node to store m ranked node as head node

  Linked_Node *node_current_m = *node_head;

 

  //set the rank as rm=1

  rm =1

  //traverse to find the m ranked node

  while (node_current_m && rm<m)

  {    

      node_prev = node_current_m;

      node_current_m = node_current_m->next;

      rm++;

  }

 

  //To find the n ranked node

  //set previous node  

  Linked_Node *node_prev_n = NULL;

 

  //set node to store n ranked node as head node

  Linked_Node *node_current_n = *node_head;

 

  //set the rank as rn=1

  rn =1

  //traverse to find the n ranked node

  while (node_current_n && rn<n)

  {    

      node_prev_n= node_current_n;

      node_current_n = node_current_n->next;

      rn++;

  }

 

  //if m is not first ranked node

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      //set node_current_n as previous node

      node_prev->next = node_current_n;

 

  //otherwise Set the node_current_n

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  // If n is not first ranked node

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  //now swap the next pointers also

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  Linked_Node *temp = node_current_n->next;

  node_current_n->next = node_current_m->next;

  node_current_m->next = temp;

}

Explanation:

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