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Sever21 [200]
3 years ago
5

The memory used by the CPU to temporarily hold data while processing is called _______. random access memory central processing

memory the hard disk long-term access memory
Computers and Technology
1 answer:
GuDViN [60]3 years ago
6 0

Answer:

primary memory

Explanation:

it holds temporarily data for processing in the RAM and ROM

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These are some way I know

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Create a structure representing a student. The member variables should include student name, student ID, and four test grades fo
Neporo4naja [7]

Answer:

Output:

Name: Brainly

ID:0001

Write the 4 tests grades of the student separated by space :10 9 8 10

Brainly

0001

10 9 8 10

Average :9.66667

'1' to continue '0' to exit :

Explanation:

#include<iostream>

#include<string>

using namespace std;

//variables declaration

struct Student {

  string id; //string declaration ID

  string name; // string declaration name

  int grades[4]; //array of 4 because it is 4 grades

};

//definition of the function get information

void inputData(Student &s){

 

   

   cout << "Name:" ;

   getline(cin,s.name);

   cout << "ID:";

   cin >> s.id;

   cout << "Write the 4 tests grades of the student separated by space :";

   for (int i = 0; i<4; i++)

       cin >> s.grades[i];

}

//definition of the function of average

double inputAvg(Student s){

   double summation;

   int temporary;

   double average;

   for (int i = 0; i<4; i++){  

      for (int j = i; j<4; j++){

         if (s.grades[j] > s.grades[i]){

             temporary = s.grades[i];

             s.grades[i] = s.grades[j];

             s.grades[j] = temporary;

         }

      }

    }

    summation = 0;

    for (int i = 0; i<3; i++){

        summation = summation + s.grades[i];  

    }

    average = summation/3;

    return average;

}

void disp(Student *s){

   cout << s->name << endl;

   cout << s->id << endl;

   for (int i = 0; i<4; i++)

       cout << s->grades[i] << " ";

   cout << endl;

   cout << "Average :" << inputAvg(*s) << endl;

   

}

int main(){

  Student st;

  int ch;

  while(true){

      inputData(st);

      disp(&st);

      cout << " '1' to continue '0' to exit :";

      cin >> ch;

      if (ch == 0)

         break;      

  }

  return 0;

}

6 0
3 years ago
Write a recursive method called repeat that accepts a string s and an integer n as parameters and that returns s concatenated to
svp [43]

Answer:

public static String repeat(String text, int repeatCount) {

   if(repeatCount < 0) {

       throw new IllegalArgumentException("repeat count should be either 0 or a positive value");

   }

   if(repeatCount == 0) {

       return "";

   } else {

       return text + repeat(text, repeatCount-1);

   }

}

Explanation:

Here repeatCount is an int value.

at first we will check if repeatCount is non negative number and if it is code will throw exception.

If the value is 0 then we will return ""

If the value is >0 then recursive function is called again untill the repeatCount value is 0.

6 0
3 years ago
Error: At least one of the class levels is not a valid R variable name; This will cause errors when class probabilities are gene
qwelly [4]

Using the knowledge in computational language in JAVA it is possible to write a code that use factor levels that can be used as valid R variable names

<h3>Writting the code in JAVA:</h3>

<em>    method  = "repeatedcv"</em>

<em>  , number  = 10</em>

<em>  , repeats = 1 </em>

<em>  , verboseIter = TRUE</em>

<em>  , summaryFunction  = fivestats</em>

<em>  , classProbs = TRUE</em>

<em>  , allowParallel = TRUE)</em>

<em />

<em />

See more about JAVA at brainly.com/question/12975450

#SPJ1

3 0
2 years ago
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