What value is added to both sides of the equation x2 − 8x = −10 in order to solve by completing the square?−816−44?

Mathematics

2 answers:

Artyom0805 [142]3 years ago

6 0

Do you see -8x?

Take half of -8 and square it.

So, (-8)/2 = -4.

(-4)^2 = 16

Now add 16 to both sides.

swat323 years ago

6 0

Answer:

The correct option is 2. 16 is added to both sides of the equation.

Step-by-step explanation:

The given equation is

$x^2-8x=-10$

If an expression is defined as $x^2+bx$ , then we need to add $(\frac{b}{2})^2$ in the expression to make it perfect square.

In the given equation b=-8.

$(\frac{b}{2})^2=(\frac{-8}{2})^2=(-4)^2=16$

We need to add 16 on both the sides to solve by completing the square.

Therefore the correct option is 2. 16 is added to both sides of the equation.

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3 years ago

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elixir [45]

Answer:

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Step-by-step explanation:

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